Question

What is the equation of a line perpendicular to y = 6x - 5 that passes through the point (6,-3)?

Answer 1

Step-by-step explanation:

The product of slope of 2 straight lines perpandicular each other is -1.

Now, The slope of the original equation is 6. We wish to find the slope m of the perpendicular line. So

$6m = - 1$

$m = - \frac{1}{6}$

Now substituting the slope m and the point (6, -3) into the perpandicular line to solve for the y intercept.

$y = mx + c$

$- 3 = 6( - \frac{1}{6} ) + c$

$c = - 2$

Therefore, the equation of the perpandicular line is

$y = - \frac{1}{6} x - 2$