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Art [367]
2 years ago
12

Will give brainliest!!!! Please help I am very stuck on this thank you. ​

Mathematics
2 answers:
sladkih [1.3K]2 years ago
8 0
20x^8 y^10 that the answer
Mice21 [21]2 years ago
3 0

Answer: 20x^8 y^10

Step-by-step explanation:

First off, simplify the exponential of x and y and the integers on the left side of the equation getting 32x^8 y^10 - 12x^8 y^10 = 20x^8 y^10

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2x(x+1)-2=2(x-3)(x+3)
Ilya [14]

Answer:

x=-8

Step-by-step explanation:

I solved for x and got this :)

Hope this helps :D

5 0
3 years ago
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Please help with all 3
DerKrebs [107]

Answer:

1, volume=23×9×5

=1035

2, volume=(1/2×5×4)×20

... =200

3.

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2 years ago
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If 2 straight lines intersect as shown, what is the value of z
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7 0
3 years ago
Factorise p^2 + 30p
Amanda [17]

Answer:

Step-by-step explanation:

hello :

p²+30p = p(p+30)

7 0
3 years ago
Given f of x is equal to 1 over the quantity x minus 3 end quantity and g of x is equal to the square root of the quantity x plu
Lostsunrise [7]

The domain of the composite function is given as follows:

[–3, 6) ∪ (6, ∞)

<h3>What is the composite function of f(x) and g(x)?</h3>

The composite function of f(x) and g(x) is given as follows:

(f \circ g)(x) = f(g(x))

In this problem, the functions are:

  • f(x) = \frac{1}{x - 3}.
  • g(x) = \sqrt{x + 3}

The composite function is of the given functions f(x) and g(x) is:

f(g(x)) = f(\sqrt{x + 3}) = \frac{1}{\sqrt{x + 3} - 3}

The square root has to be non-negative, hence the restriction relative to the square root is found as follows:

x + 3 \geq 0

x \geq -3

The denominator cannot be zero, hence the restriction relative to the denominator is found as follows:

\sqrt{x + 3} - 3 \neq 0

\sqrt{x + 3} \neq 3

(\sqrt{x + 3})^2 \neq 3^2

x + 3 \neq 9

x \neq 6

Hence, from the restrictions above, of functions f(x), g(x) and the composite function, the domain is:

[–3, 6) ∪ (6, ∞)

More can be learned about composite functions at brainly.com/question/13502804

#SPJ1

7 0
1 year ago
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