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Elza [17]
2 years ago
13

2(2t+4)=3/4(24−8t) please help

Mathematics
1 answer:
Tcecarenko [31]2 years ago
5 0

Step-by-step explanation:

the process is shown above hope you understand.

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What formula is used to find 44% of 8?<br><br>​
-BARSIC- [3]
The formula is 8x.44
6 0
3 years ago
Please help asap (17 points) thankyou
masha68 [24]

Answer:

median: 28

mean: 55 + 25 + 28 + 42 + 25 = 175    175 / 5= 35

Step-by-step explanation:

median is the number that is in the middle of all of the other numbers

mean is when you add all of the numbers together and then divide the total depending how many numbers you added together.

5 0
3 years ago
Read 2 more answers
I NEED HELP IDENTIFYING THE SLOPE PLEASE !!! Pic attatched !!!!
Alexus [3.1K]

Answer:

see explanation

Step-by-step explanation:

Calculate the slope m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = 2,4 ) and (x₂, y₂ ) = (5, 1)

m = \frac{1-4}{5-2}  = \frac{-3}{3} = - 1 ← negative slope

Repeat

with (x₁, y₁ ) = - 7,8) and (x₂, y₂ ) = (- 7, 0)

m = \frac{0-8}{-7+7} = \frac{-8}{0}

Division by zero is undefined, thus slope is undefined.

Repeat with

(x₁, y₁ ) = (6, - 3) and (x₂, y₂ ) = (- 4, - 3)

m = \frac{-3+3}{-4-6} = \frac{0}{-10} = 0 ← zero slope

Repeat with

(x₁, y₁ ) = (3, 5) and (x₂, y₂ ) = (- 1, 2)

m = \frac{2-5}{-1-3} = \frac{-3}{-4} = \frac{3}{4} ← positive slope

7 0
2 years ago
Find the area of each triangle o the nearest tenth.
blagie [28]

Answer:

A is , 18.1058 B is  , 24.91575

Step-by-step explanation:

6 0
2 years ago
Find the sum of the series Summation from n equals 1 to infinity (StartFraction 3 Over StartRoot n plus 2 EndRoot EndFraction mi
Marizza181 [45]

Looks like the series is supposed to be

\displaystyle\sum_{n=1}^\infty\frac3{\sqrt{n+2}}-\frac3{\sqrt{n+3}}

The series telescopes; consider the kth partial sum of the series,

S_k=\displaystyle\sum_{n=1}^k\frac3{\sqrt{n+2}}-\frac3{\sqrt{n+3}}

S_k=\displaystyle\left(\frac3{\sqrt3}-\frac32\right)+\left(\frac32-\frac3{\sqrt5}\right)+\cdots+\left(\frac3{\sqrt{k+1}}-\frac3{\sqrt{k+2}}\right)+\left(\frac3{\sqrt{k+2}}-\frac3{\sqrt{k+3}}\right)

\implies S_k=\dfrac3{\sqrt3}-\dfrac3{\sqrt{k+3}}

As k\to\infty, the second term converges to 0, leaving us with

\displaystyle\sum_{n=1}^\infty\frac3{\sqrt{n+2}}-\frac3{\sqrt{n+3}}=\frac3{\sqrt3}=\boxed{\sqrt3}}

7 0
2 years ago
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