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3 years ago

A ceramic tile in the shape of a parallelogram has a base of 4 inches and a height of 1.5 inches. What is the area of the tile?

Mathematics

2 answers:

kondor19780726 [428]3 years ago

3 0

Answer:

6 in^2

Step-by-step explanation:

Trava [24]3 years ago

3 0

Answer:

Step-by-step explanation:

if you need all of it then 6 in^2 there hope it helps

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Greater number832458or 83250

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Solve the following equation:<br> 1-31 x 8 = x<br> X =

Yuki888 [10]

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The square root of a negative number is not a real number

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Brrunno [24]

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Please help logarithms!

nlexa [21]

Given:

$\log_34\approx 1.262$

$\log_37\approx 1.771$

To find:

The value of $\log_3\left(\dfrac{4}{49}\right)$ .

Solution:

We have,

$\log_34\approx 1.262$

$\log_37\approx 1.771$

Using properties of log, we get

$\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_349$ $\left[\because \log_a\dfrac{m}{n}=\log_am-\log_an\right]$

$\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_37^2$

$\log_3\left(\dfrac{4}{49}\right)=\log_34-2\log_37$ $[\log x^n=n\log x]$

Substitute $\log_34\approx 1.262$ and $\log_37\approx 1.771$ .

$\log_3\left(\dfrac{4}{49}\right)=1.262-2(1.771)$

$\log_3\left(\dfrac{4}{49}\right)=1.262-3.542$

$\log_3\left(\dfrac{4}{49}\right)=-2.28$

Therefore, the value of $\log_3\left(\dfrac{4}{49}\right)$ is $-2.28$ .

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3 years ago

Help plsssssssss ....

Rom4ik [11]

Answer:

Arccos(0.9272) =0.383929333 radian

0.383929333 radian =(0.383929333*57.2957795)degrees

so, 21.99 degrees

Step-by-step explanation:

Rounding to the nearest we get 22 degrees

We know that,

1 radian is equal to 57.2957795

so we multiply the radian value 0.383929333 with it

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2 years ago