I believe its 2. 4*2=8. 2*7=14. 2*10=20
Answer:
The population of deer at any given time = 200(e^0.03t) ÷ (1.5 + (e^0.03t))
Step-by-step explanation:
This is an example of logistic equation on population growth
carrying capacity, k = 200
Rate, r = 3% = 0.03
Initial Population, P1 = 80
P(t) =?
P(t) = (P1 (k)(e^rt)) ÷ (k- P1 + P1(e^rt))
P(t) = (80 (200)(e^0.03t)) ÷ (200 - 80 + 80(e^0.03t))
= (16000(e^0.03t)) ÷ (120 + 80(e^0.03t))
= 200(e^0.03t) ÷ (1.5 + (e^0.03t))
Answer:
okay
Step-by-step
no of yards they cut in an hour
Jacob = 2 yard
jenny 3/4 of a yard
no of yards it will take jenny to cut 3 yards = 4 hours
Answer:
Step-by-step explanation:
Given the expression
Remove the parentheses
Group like terms
simplifying
Therefore, the equivalent expression with 3 terms for the expression is:
