The red marble is farthest from the target.
The X and Y angles created by lines intersection in the pictures are 18° and 54°.
Based on the picture, angle ∠MON is a right angle hence it has an 90° angle. We then know that the ∠MOA is 72°. Because angle ∠MOA lies within the angle ∠MON, hence we can write the following formula:
∠MON = ∠MOA +∠AON = 90°
∠MON = 72° + ∠AON = 90°
∠AON = 18° ... (i)
If we focus on the line CD being intersected by the line AB, hence we can conclude that the angles form by this intersection will follow these rules:
∠AOD = ∠BOC
∠AOC = ∠BOD
∠AOD + AOC = 180°
∠BOC + ∠BOD = 180°
Based on the picture, we know that:
∠BOC = x
∠AOC = ∠MOA + ∠MOC
∠AOC = 72° + y ...(ii)
∠AOD = ∠AON + ∠NOD
∠AOD = 18° +2x
∠BOC = 3x ... (iii)
Because we already know that ∠BOC = AOD, hence we could rewrite the formula into:
∠BOC = ∠AOD
3x = 18° + 2x
x = 18° ... (iv)
To find the value of y, we need to focus on angle ∠AOC. Based on the previous calculations and formulas, we know that:
∠AOC + ∠BOC = 180° ... (v)
Input equations (ii) and (iv) into (v)
∠AOC + ∠BOC = 180°
(72° + y) + 3x = 180°
72° + y + 3(18°) = 180°
126° + y = 180°
y = 54° ... (vi)
Learn more about the angles by lines intersection here: brainly.com/question/2077876?referrer=searchResults
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Answer:
The correct answer is A.
Step-by-step explanation:
Method 1
You just have to plot each point on the graph.
The one that falls within the solution region is the correct choice.
From the graph, falls within the solution region.
See graph
Method 2
If you substitute the points into the inequalities, the only point that will satisfy both inequalities simultaneously is A.
The first inequality is
If we substitute , we get;
This statement is true.
The second inequality is
If we substitute , we get;
This gives,
This statement is also true.
Answer:
1st - Yes ; 2nd - Yes ; 3rd - Yes ; 4th - No
Step-by-step explanation:
Answer:
(9b + 3c + 10d)cm
Step-by-step explanation:
Given the sides of a triangle expressed as (2b+c), (7b + 4d) and (6d+2c). The perimeter of the triangle is the sum of all the sides of the triangles.
Perimeter of the triangle = 2b+c + 7b+4d + 6d+2c
Perimeter of the triangle = 2b + 7b + c + 2c + 4d + 6d
Perimeter of the triangle = 9b + 3c + 10d
Hence the perimeter of the triangle is (9b + 3c + 10d)cm
