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serg [7]
3 years ago
6

Select the correct answer.

Mathematics
1 answer:
frosja888 [35]3 years ago
5 0

Answer:

the correct answer is A : 2x3-1

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Help Me Please I will Give Brainliest If Correct!!!
disa [49]

Answer:

8^-2a^7 = a^7/8^2 = a^7/64

Step-by-step explanation:

6 0
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In a science test Jamie solved 42 correct and 18 incorrect answers what is the percentage of correct questions
Mkey [24]
The percentage is 2.3
6 0
4 years ago
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What is the nonpermissible value of x in 5x/6x+3
cestrela7 [59]

Answer: -\frac{1}{2}

<u>Step-by-step explanation:</u>

\frac{5x}{6x+3}

Restriction: 6x + 3 ≠ 0     <em>denominator cannot be zero</em>

                   <u>     -3  </u>  <u> -3 </u>

                    6x      ≠ -3

                 <u> ÷6       </u>   <u>÷6 </u>

                      x       ≠ -\frac{1}{2}

4 0
3 years ago
The Pew Research Center reported that 73% of Americans who own a cell phone also use text messaging. In a recent local survey, 1
AnnZ [28]

Answer:

z=\frac{0.775 -0.73}{\sqrt{\frac{0.73(1-0.73)}{200}}}=1.433  

Now we can find the p value. Since we have a bilateral test the p value would be:  

p_v =2*P(z>1.433)=0.152  

Since the p value is higher than the significance level of 0.1 we have enough evidence to FAIL to reject the null hypothesis and the best conclusion for this case would be:

Do Not reject H0

Step-by-step explanation:

Information provided

n=200 represent the sample size slected

X=155 represent the cell phone owners used text messaging

\hat p=\frac{155}{200}=0.775 estimated proportion of cell phone owners used text messaging

p_o=0.73 is the value to verify

\alpha=0.1 represent the significance level

We need to conduct a z test for a proportion

z would represent the statistic

p_v represent the p value

System of hypothesis

We want to verify if the true proportion of cell phone owners used text messaging is different from 0.73 so then the system of hypothesis are:

Null hypothesis:p=0.73  

Alternative hypothesis:p \neq 0.73  

The statistic to check this hypothesis is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing the data given we got:

z=\frac{0.775 -0.73}{\sqrt{\frac{0.73(1-0.73)}{200}}}=1.433  

Now we can find the p value. Since we have a bilateral test the p value would be:  

p_v =2*P(z>1.433)=0.152  

Since the p value is higher than the significance level of 0.1 we have enough evidence to FAIL to reject the null hypothesis and the best conclusion for this case would be:

Do Not reject H0

6 0
3 years ago
Susan decided to start a bracelet business. She spent $17.75 on supplies for her
Snezhnost [94]

Answer:

Given that:

Susan spent on supplies = $17.75

Earning of june = 24 * $3.25

Earning of June = $78

1/4 of earning = 1/4 * 78

1/4 of earning = $19.5

So Susan will set $19.5 aside for supplies of next month and remaining amount she will have is : 78 - 19.5 = $58.5

i hope it will help you!

6 0
3 years ago
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