Slope is your 2x, so 2x over 1 meaning after you plot (-2,2) on the graph you rise 2 and go 1 to the right, or do the opposite to make the line so go down 2 and one to the left. Hope that helped.
Answer:
156.5
Step-by-step explanation:
Thinking process:
The area can be calculated using the formula:

We let the substitution take place.
Therefore, we let 
Thus, 
So,

Also, the interval of the integration changes to [ 37, 65]
Thus,

= 
= 156.5 units²
1) -8 and 3
because -8+3= -5 and -8x3=24
2) -8 and -5
because -8-5=-13 and -8x-5=40
Layla bu la 520 and glue 729
Answer:
If our random variable of interest for this case is X="the number of teenagers between 12-17 with smartphone" we can model the variable with this distribution:

And the mean for this case would be:

And the standard deviation would be given by:

Step-by-step explanation:
If our random variable of interest for this case is X="the number of teenagers between 12-17 with smartphone" we can model the variable with this distribution:

And the mean for this case would be:

And the standard deviation would be given by:
