Consider U = {x|x is a real number}.
2 answers:
Answer:
Option c.
Step-by-step explanation:
We have the set of real numbers greater than 8 and B the set of real numbers greater than 5 here:
A: x+2>10 ⇒ x>8
B: 2x > 10 ⇒ x>5
8∉A ; 8∈B
Note: We can see (graph) that the intervals are open, so the corresponding points do not belong to their respective sets.
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Answer:
Using the frequency distribution, I found the mean height to be 70.2903 with a standard deviation of 3.5795
Step-by-step explanation:
Given
See attachment for class
Solving (a): Fill the midpoint of each class.
Midpoint (M) is calculated as:
Where
Lower class interval
Upper class interval
So, we have:
Class 63-65:
Class 66 - 68:
When the computation is completed, the frequency distribution will be:
Solving (b): Mean and standard deviation using 1-VarStats
Using 1-VarStats, the solution is:
<em>See attachment for result of 1-VarStats</em>
