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2 years ago

Can someone help me please?

Mathematics

2 answers:

kodGreya [7K]2 years ago

8 0

2/4 = 0.5
3/4 = 0.75
7/8 = 0.875
3/8 = 0.375

Marrrta [24]2 years ago

4 0

$\\ \sf\longmapsto \dfrac{2}{4}$

$\\ \sf\longmapsto \dfrac{1}{2}$

$\\ \sf\longmapsto \dfrac{1(5)}{2(5)}$

$\\ \sf\longmapsto \dfrac{5}{10}$

$\\ \sf\longmapsto 0.5$

$\\ \sf\longmapsto \dfrac{3}{4}$

$\\ \sf\longmapsto \dfrac{3(25)}{4(25)}$

$\\ \sf\longmapsto \dfrac{75}{100}$

$\\ \sf\longmapsto 0.75$

$\\ \sf\longmapsto \dfrac{7}{8}$

$\\ \sf\longmapsto \dfrac{7(125)}{8(125)}$

$\\ \sf\longmapsto \dfrac{875}{1000}$

$\\ \sf\longmapsto 0.875$

$\\ \sf\longmapsto \dfrac{3}{8}$

$\\ \sf\longmapsto \dfrac{3(125)}{8(125)}$

$\\ \sf\longmapsto \dfrac{375}{1000}$

$\\ \sf\longmapsto 0.375$

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LOTS OF POINTS GIVING BRAINLIEST I NEED HELP PLEASEE

Sidana [21]

Answer:

Segment EF: y = -x + 8

Segment BC: y = -x + 2

Step-by-step explanation:

Given the two similar right triangles, ΔABC and ΔDEF, for which we must determine the slope-intercept form of the side of ΔDEF that is parallel to segment BC.

Upon observing the given diagram, we can infer the following corresponding sides:

$\displaystyle\mathsf{\overline{BC}\:\: and\:\:\overline{EF}}$

$\displaystyle\mathsf{\overline{BA}\:\: and\:\:\overline{ED}}$

$\displaystyle\mathsf{\overline{AC}\:\: and\:\:\overline{DF}}$

We must determine the slope of segment BC from ΔABC, which corresponds to segment EF from ΔDEF.

<h2>Slope of Segment BC:</h2>

In order to solve for the slope of segment BC, we can use the following slope formula:

$\displaystyle\mathsf{Slope\:(m)\:=\:\frac{y_2 \:-\:y_1}{x_2 \:-\:x_1}} }$

Use the following coordinates from the given diagram:

Point B: (x₁, y₁) = (-2, 4)

Point C: (x₂, y₂) = ( 1, 1 )

Substitute these values into the slope formula:

$\displaystyle\mathsf{Slope\:(m)\:=\:\frac{y_2 \:-\:y_1}{x_2 \:-\:x_1}}\:=\:\frac{1\:-\:4}{1\:-\:(-2)}\:=\:\frac{-3}{1\:+\:2}\:=\:\frac{-3}{3}\:=\:-1}$

<h2>Slope of Segment EF:</h2>

Similar to how we determined the slope of segment BC, we will use the coordinates of points E and F from ΔDEF to find its slope:

Point E: (x₁, y₁) = (4, 4)

Point F: (x₂, y₂) = (6, 2)

Substitute these values into the slope formula:

$\displaystyle\mathsf{Slope\:(m)\:=\:\frac{y_2 \:-\:y_1}{x_2 \:-\:x_1}}\:=\:\frac{2\:-\:4}{6\:-\:4}\:=\:\frac{-2}{2}\:=\:-1}$

Our calculations show that segment BC and EF have the same slope of -1. In geometry, we know that two nonvertical lines are <u>parallel</u> if and only if they have the same slope.

Since segments BC and EF have the same slope, then it means that $\displaystyle\mathsf{\overline{BC}\:\: | |\:\:\overline{EF}}$ .

<h2>Slope-intercept form:</h2><h3><u>Segment BC:</u></h3>

The <u>y-intercept</u> is the point on the graph where it crosses the y-axis. Thus, it is the value of "y" when x = 0.

Using the slope of segment BC, m = -1, and the coordinates of point C, (1, 1), substitute these values into the <u>slope-intercept form</u> (y = mx + b) to solve for the y-intercept, <em>b. </em>

y = mx + b

1 = -1( 1 ) + b

1 = -1 + b

Add 1 to both sides to isolate b:

1 + 1 = -1 + 1 + b

2 = b

Hence, the <u><em>y-intercept</em></u> of segment BC is: <em>b</em> = 2.

Therefore, the linear equation in <u>slope-intercept form of segment BC</u> is:

⇒ y = -x + 2.

<h3><u /></h3><h3><u>Segment EF:</u></h3>

Using the slope of segment EF, <em>m</em> = -1, and the coordinates of point E, (4, 4), substitute these values into the <u>slope-intercept form</u> to solve for the y-intercept, <em>b. </em>

y = mx + b

4 = -1( 4 ) + b

4 = -4 + b

Add 4 to both sides to isolate b:

4 + 4 = -4 + 4 + b

8 = b

Hence, the <u><em>y-intercept</em></u> of segment BC is: <em>b</em> = 8.

Therefore, the linear equation in <u>slope-intercept form of segment EF</u> is:

⇒ y = -x + 8.

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2 years ago

Look at the image. (calculus)

mash [69]

<h3>Answer: Choice H) 2</h3>

=============================================

Explanation:

Recall that the pythagorean trig identity is $\sin^2 x + \cos^2x = 1$

If we were to isolate sine, then,

$\sin^2 x + \cos^2x = 1\\\\\sin^2 x = 1-\cos^2x\\\\\sin x = \sqrt{1-\cos^2x}\\\\$

We don't have to worry about the plus minus because sine is positive when 0 < x < pi/2.

Through similar calculations, $\cos x = \sqrt{1-\sin^2x}\\\\$

Cosine is also positive in this quadrant.

-------------

So,

$\frac{\sqrt{1-\cos^2x}}{\sin x}+\frac{\sqrt{1-\sin^2x}}{\cos x}\\\\\frac{\sin x}{\sin x}+\frac{\cos x}{\cos x}\\\\1+1\\\\2$

Therefore,

$\frac{\sqrt{1-\cos^2x}}{\sin x}+\frac{\sqrt{1-\sin^2x}}{\cos x}=2$

is an identity as long as 0 < x < pi/2

5 0

1 year ago

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Angle P measures 112 degrees, what are the measures of angle N and O?

Oxana [17]

The inside angles of a triangle need to equal 180 degrees
in this triangle the lines NP and OP are identical so the 2 unknown angles would be equal
so the 2 unknown angles would be 180 - 112 = 68 / 2 = 34 each
angle N & O are 34 degrees

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3 years ago

A sequence is defined recursively using the formula f(n + 1) = -0.5f(n). If the first term of the sequence is 120, what is f(5)?

PolarNik [594]

Answer: 7.5

Step-by-step explanation:

The given formula tells us that the next term f(n+1) of the sequence is -0.5 times the previous term f(n)

First term of the sequence is f(1) = 120

Second term of the sequence is f(2) = f(1+1) = -0.5 f(1) = -0.5 (120) = -60

Third term of the sequence is f(3) = f(2+1) = -0.5 f(2) = -0.5 (-60) = 30

Fourth term of the sequence is f(4) = f(3+1) = -0.5 f(3) = -0.5 (30) = -15

Fifth term of the sequence is f(5) = f(4+1) = -0.5 f(4) = -0.5 (-15) = <em>7.5</em>

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3 years ago

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Answer:

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Step-by-step explanation:

In order to calculate the total amount of hamburger meat that Ben would need we would need to multiply the total number of burgers that he wants to make (19) by the amount of meat each burger will use (1/4 pound or 0.25 pound). Therefore, we would do the following...

19 * 0.25 = 4.75 pounds

Finally, we can see that Ben would need a total of 4.75 pounds of hamburger meat to make 19 equal sized 1/4 pound burgers.

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2 years ago