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Xelga [282]
3 years ago
10

Can someone help me please?

Mathematics
2 answers:
kodGreya [7K]3 years ago
8 0
2/4 = 0.5
3/4 = 0.75
7/8 = 0.875
3/8 = 0.375
Marrrta [24]3 years ago
4 0

\\ \sf\longmapsto \dfrac{2}{4}

\\ \sf\longmapsto \dfrac{1}{2}

\\ \sf\longmapsto \dfrac{1(5)}{2(5)}

\\ \sf\longmapsto \dfrac{5}{10}

\\ \sf\longmapsto 0.5

#2

\\ \sf\longmapsto \dfrac{3}{4}

\\ \sf\longmapsto \dfrac{3(25)}{4(25)}

\\ \sf\longmapsto \dfrac{75}{100}

\\ \sf\longmapsto 0.75

#3

\\ \sf\longmapsto \dfrac{7}{8}

\\ \sf\longmapsto \dfrac{7(125)}{8(125)}

\\ \sf\longmapsto \dfrac{875}{1000}

\\ \sf\longmapsto 0.875

#3

\\ \sf\longmapsto \dfrac{3}{8}

\\ \sf\longmapsto \dfrac{3(125)}{8(125)}

\\ \sf\longmapsto \dfrac{375}{1000}

\\ \sf\longmapsto 0.375

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qaws [65]

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Step-by-step explanation:

Given the joint cumulative distribution of X and Y as

F(x,y) = \frac{xy(x+y)}{2000000}\ \ \ \, \ 0\leq x100, 0\leq y\leq 100

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F_x(x)=F(x,100)\\\\\\=\frac{100x(x+100)}{2000000}\\\\\\\\=\frac{100x^2+10000x}{2000000}\\\\\\=>f_x(x)=\frac{x}{10000}+\frac{1}{200}

#Have determined the probability distribution unction ,f_x(x), we calculate the Expectation of the random variable X:

E(X)=\int\limits^{100}_0 \frac{x^2}{10000}+\frac{x}{200}  dx \\\\\\\\=|\frac{x^3}{30000}+\frac{x^2}{400}|\limits^{100}_0\\\\=58.33\\\\

#We then calculate E(X^2):

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