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3 years ago

In the dig ram below line l is parallel to line m. Which angles are congruent to angle 1

Mathematics

1 answer:

mixas84 [53]3 years ago

4 0

Answer:

3, 8, 6

Step-by-step explanation:

The angles that are congruent to angle 1 are: 3, 8, 6

Answer: Congruent angles are 3, 8, 6

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Referring to the figure, find the value of x

bekas [8.4K]

Answer:I think it’s 75 divided by 5

Step-by-step explanation:

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4 years ago

Firewood is usually sold by a measure known as a cord. A full cord may be a stack 8*4

densk [106]

Where might the question be

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3 years ago

Hese are the values in Paul’s data set.

andrew-mc [135]

Answer: See description below.

The residuals are the differences between the predicted values and the actual values. You will need to make a scatter plot of each difference.

Here are the five points that you will need to plot:
20 - 21 = -1 (1, -1)
17 - 16 = 1 (2, 1)
9 - 10 = -1 (4, -1)
6 - 5 = 1 (5, 1)
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8 0

3 years ago

Read 2 more answers

List all possible dimensions of rectangle with an area of 24 square feet

max2010maxim [7]

L=1 w=24

L=24 w=1

L=2 w= 12

L=12 w=2

L=3 w=8

L=8 w=3

L=4 w=6

L=6 w=4

I think

6 0

3 years ago

A tire manufacturer wants to estimate the average number of miles that may be driven in a tire of a certain type before the tire

alexandr402 [8]

Answer:

97% confidence interval for the average number of miles that may be driven is [26.78 miles, 33.72 miles].

Step-by-step explanation:

We are given that a random sample of tires is chosen and are driven until they wear out and the number of thousands of miles is recorded;

32, 33, 28, 37, 29, 30, 22, 35, 23, 28, 30, 36.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample average number of miles = $\frac{\sum X}{n}$ = 30.25

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = 4.71

n = sample of tires = 12

$\mu$ = population average number of miles

Here for constructing a 97% confidence interval we have used One-sample t-test statistics as we don't know about population standard deviation.

So, 97% confidence interval for the population mean, $\mu$ is ;

P(-2.55 < $t_1_1$ < 2.55) = 0.97 {As the critical value of t at 11 degrees of

freedom are -2.55 & 2.55 with P = 1.5%}

P(-2.55 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.55) = 0.97

P( $-2.55 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.55 \times {\frac{s}{\sqrt{n} } }$ ) = 0.97

P( $\bar X-2.55 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.55 \times {\frac{s}{\sqrt{n} } }$ ) = 0.97

97% confidence interval for $\mu$ = [ $\bar X-2.55 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.55 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $30.25-2.55 \times {\frac{4.71}{\sqrt{12} } }$ , $30.25+2.55 \times {\frac{4.71}{\sqrt{12} } }$ ]

= [26.78 miles, 33.72 miles]

Therefore, 97% confidence interval for the average number of miles that may be driven is [26.78 miles, 33.72 miles].

7 0

4 years ago