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Masja [62]
1 year ago
5

A quadratic function and an exponential function are graphed below. How do the decay rates of the functions compareover the inte

rval -2

Mathematics
1 answer:
Kobotan [32]1 year ago
4 0

To check the decay rate, we need to check the variation in y-axis.

Since our interval is

-2We need to evaluate both function at those limits.At x = -2, we have a value of 4 for both of them, at x = 0 we have 1 for the exponential function and 0 to the quadratic function. Let's call the exponential f(x), and the quadratic g(x).[tex]\begin{gathered} f(-2)=g(-2)=4 \\ f(0)=1 \\ g(0)=0 \end{gathered}

To compare the decay rates we need to check the variation on the y-axis of both functions.

\begin{gathered} \Delta y_1=f(-2)-f(0)=4-1=3 \\ \Delta y_2=g(-2)-g(0)=4-0=4 \end{gathered}

Now, we calculate their ratio to find how they compare:

\frac{\Delta y_1}{\Delta y_2}=\frac{3}{4}

This tell us that the exponential function decays at three-fourths the rate of the quadratic function.

And this is the fourth option.

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Answer:

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Step-by-step explanation:

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x = 65

5 0
3 years ago
Please help fast! give me the equation
uranmaximum [27]

\begin{bmatrix}x=\frac{\pi }{2}+2\pi n\\ x=\frac{3\pi }{2}+2\pi n\\ x=\frac{3\pi }{4}+\pi n\\ x=\frac{7\pi }{4}+\pi n\end{bmatrix}

\begin{bmatrix}\frac{3\pi }{2}+2\pi n=\frac{\pi }{2}+2\pi n\\ \frac{3\pi }{2}+2\pi n=\frac{3\pi }{4}+\pi n\\ \frac{3\pi }{2}+2\pi n=\frac{7\pi }{4}+\pi n\end{bmatrix}

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- hope this helps! -

6 0
2 years ago
If the area around the vegetable garden is of uniform width (labeled with x) and the dimensions of the vegetable garden is 45 fe
Nady [450]
Area of Rectangle = Width × Length

Vegetable Garden
Width = 20
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Area of Vegetable Garden = 20×45=900 Sq ft

Area of Entire Garden = Width × Length
Width = 20 + 2x
Length = 45 + 2x
Area = (20 + 2x)(45 + 2x)
(2x + 20)(2x + 45)
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Area of Flower Garden = Area of Entire Garden - Area of Vegetable Garden

(4x^2 + 135x + 900) - (20 × 45)
4x^2 + 135x + 900 - 900
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7 0
3 years ago
PLEEAASE HELP MEEEEEE
Gre4nikov [31]

\mathsf{1.\; \frac{x - 6}{2} = x + 13}

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So, It matches with A in Column B

2. 2 + 6x - 7 = 8 + 2x - 10 + 4x

⇒ 6x - 5 = 6x - 2

As, They are Equations of Parallel Lines. They never meet each other.

⇒ This Equation has No Solution

⇒ So, It matches with B in Column B

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As, They are Equations of Parallel Lines. They never meet each other.

⇒ This Equation has No Solution

⇒ So, It matches with B in Column B

4. 16 + 8x = 4(2x + 4)

⇒ 16 + 8x = 16 + 8x

As, Both Equations are Same. They Represent the Same Line.

⇒ This Equation has Infinite Number of Solutions

⇒ So, It matches with C in Column B

8 0
3 years ago
Find all polar coordinates of point P = (6, 31°).
alex41 [277]
(6,(31pi/180)+2 n pi) (-6,(31pi/180)+2 n pi) <span>
</span>
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3 years ago
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