A) Here, sum of two non-adjacent angles: 52 + 25 = 77
Now, ∠3 = 180 - 77 [ sum of all angles in a triangle is 180 ]
so, ∠3 = 103
Now, ∠3 + ∠4 = 180 [ Supplementary angles ]
So, ∠4 = 180 - ∠3
∠4 = 180 - 103 = 77
∠4 = 77 [ which is sum of two non-adjacent angles ]
....Hence proved.
b) m∠4 = 77
[ Solved in previous section ]
Hope this helps!
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Answer:
3
- 11
- 4x³ + 3x² + x
Step-by-step explanation:
(x³ - 4x² + 1)(3x² + x)
Each term in the second factor is multiplied by each term in the first factor, that is
x³(3x² + x) - 4x²(3x² + x) + 1 (3x² + x) ← distribute parenthesis
= 3
+
- 12
- 4x³ + 3x² + x ← collect like terms
= 3
- 11
- 4x³ + 3x² + x
Remembering PEMDAS we solve like this
5•6=30 6÷2=3 30-3=27
27 is answer. it is easy, just replace the letter with the number and solve it