Given :
Temperature, T = 55° C = ( 55 + 273 ) K = 328 K .
Volume of container, V = 28.9 dm³ = 0.0289 m³ .
Pressure, P = 144 kPa = 144000 Pa .
To Find :
Number of moles of nitrogen gas.
Solution :
We know, by ideal gas equation :
PV = nRT ( R ( universal gas constant ) = 8.31 J K⁻¹ mol⁻¹ .
Therefore, number of moles of nitrogen gas is 1.53 moles.
They all have 2 elections in the outer S orbital, and 4 electrons in the P orbitals.
Answer:
The molecular equation for the reaction of CaCO₃ with CH₃COOH is:
CaCO₃ (s) + 2CH₃COOH (aq) → Ca(CH₃COO)₂ (aq) + H₂O (l) + CO₂ (g)
Option 1
Explanation:
CaCO₃ + 2CH₃COOH → Ca(CH₃COO)₂ + H₂O + CO₂
Option 3 is the same equation as option 1, but calcium acetate, does not precipitate, so the formed salt, is not a solid.
Option 2 and 4 are wrong because calcium acetate molecular formula is
Ca(CH₃COO)₂
Ca(CH₃COO)₂ → Ca²⁺ + 2 CH₃COO⁻
D. uranium: atomic number 92, mass 238, neutrons 146
238-92=146
