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sweet-ann [11.9K]
4 years ago
7

What happens to iron when iron oxide becomes elemental iron?

Chemistry
2 answers:
Ilya [14]4 years ago
6 0
The appropriate response is Reduction. It is a chemical reaction that includes the picking up of electrons. It alludes to the side that acknowledges electrons. At the point when iron responds with oxygen, it frames a concoction called rust. In that case, the iron is oxidized and the oxygen is lessened.
Ierofanga [76]4 years ago
6 0

Answer:

Iron gets reduced from a +3 oxidation state to 0

Explanation:

The decomposition of iron oxide to elemental can be represented by the following equation:

2Fe_{2} O_{3} (s)------ 4Fe(s) + 3O_{2} (g)

In iron oxide (Fe2O3), the oxidation state of iron is +3 while that of oxygen is -2. Therefore, the above reaction is a redox (reduction oxidation reaction).

Here, iron in iron oxide gains 3 electrons and gets reduced from Fe3+ to Fe(0). Whereas, the oxygen loses 2 electrons and gets reduced from O2- to O(0).

The half reactions can be represented as:

Reduction:

Fe^{3+} + 3e- ------- Fe

Oxidation:

O^{2-} -------O + 2e-

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Gold is alloyed with other metals to increase its hardness in making jewelery.a) Consider a piece of gold jewelry the weighs 9.8
irinina [24]

Answer:

A). Percentage of gold by mass of the jewellery =

(6.059÷9.85) × 100 = 61.5%

B). Purity of the gold = 0.615 × 24 = 14.76 karat ~ 15 karat gold

Explanation:

Mass of jewellery = 9.85g Volume of jewellery = 0.675cm^3.

Density of gold = 19.3g/cm^3 and density of silver = 10.5g/cm^3

Let the volume of gold in the jewellery be X and the volume of silver in the jewellery be Y

Hence we have

Density = mass/volume or mass = volume × density = for gold = X × 19.3g/cm^3 and for the silver = Y × 10.5g/cm^3

19.3X +10.5Y = 9.85g

Also volume of jewellery is given by

Volume of silver in the jewellery + volume of gold in the jewellery = 0.675cm^3.

X + Y = 0.675cm^3.

Solving the above equations we have

Y = 0.675 - X

Which gives

19.3X + 10.5Y = 9.85g

19.3X + 10.5 × (0.675 - X) =9.85g

19.3X + 7.0875 - 10.5X = 9.85

8.8X + 7.0875 = 9.85

8.8X = 2.7625

or X = 0.3139 cm^3

But Y = 0.675 - X

Hence Y = 0.675 - 0.3139 = 0.3611 cm^3

Mass of gold in the jewellery = volume of gold × Density of gold = 0.3139 × 19.3 = 6.059 g

Also mass of silver = 10.5 × 0.3611 = 3.7913g

A). Percentage of gold by mass of the jewellery =

(6.059÷9.85) × 100 = 61.5%

B). Purity of the gold = 0.615 × 24 = 14.76 karat ~ 15 karat gold

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