Question

determine the final temperature of a gold nugget parentheses Mass equals 376 G parentheses that starts at 398k and loses 4.85 KJ of heat to a snowbank when it is lost. The specific heat capacity of gold is 0.128 J/g degrees C

Answer 1

Answer:

297.23 K

Explanation:

Given that:

the mass of the gold nugget (m) = 376 g

the initial temperature $T_1$ = 398 K

amount of heat lost Q = -4.85 kJ = -4.85 × 10³

specific heat capacity (c) = 0.128 J/g° C

Using the formula for calculating the Heat energy

$Q = mc\Delta T \\ \\ Q = m\times c\times (T_2-T_1)$

$-4.85 \times 10^3 = 376 \times 0.128 \times (T_2 - 398) \\ \\ -4.85\times 10^3 = 48.128(T_2 - 398) \\ \\ \dfrac{-4.85\times 10^3}{48.128}= (T_2 - 398) \\ \\-100.77 = T_2 -398\\\\T_2 = -398 +100.77\\ \\ \mathbf{ T_2 = 297.23K}$