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kondaur [170]
3 years ago
15

What type of algebraic expression is 4x + 5?

Mathematics
2 answers:
andriy [413]3 years ago
8 0

This is a binomial algebraic expression,buddy!

liq [111]3 years ago
6 0

Answer:

4x + 5 is a polynomial as well as a binomial.

Step-by-step explanation:

The expression 4x + 5 has two monomials 4x and 5 and this makes it a binomial. Now, the second thing to keep in mind is, every binomial is also considered a polynomial as well.

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How would you estimate the price if a shirt that usually costs $32.99 is on sale for 25% off?
Nuetrik [128]

Answer:

32.99/4 is about 8.25

8.25 x 3= 24.75

about 24.75

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Find the product of ( 2a2– 3b2) and ( a +b2- 3z)​
Bond [772]

Answer:

2a^3+2a^2b^2-6a^2z-3ab^2-3b^4+9b^2z

Step-by-step explanation:

(2a^2-3b^2)(a+b^2-3z)

Start by distributing the 2a^2 into all of the terms in between the second parentheses.

2a^3+2a^2b^2-6a^2z

Next, distribute the -3b^2 into all of the terms in between the second parentheses.

-3ab^2-3b^4+9b^2z

For the sake of simpler interpretation, I separated the two above, but they are together:

2a^3+2a^2b^2-6a^2z-3ab^2-3b^4+9b^2z

Since the terms are already in descending order, we do not need to rearrange them.

4 0
3 years ago
What is the period and midline?
OverLord2011 [107]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{  A}}cos({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\

\end{array}\qquad

\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{  A}}|\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\
\bullet \textit{vertical shift by }{{  D}}\\
\qquad if\ {{  D}}\textit{ is negative, downwards}\\
\qquad if\ {{  D}}\textit{ is positive, upwards}\\


\end{array}

\bf \begin{array}{llll}
\bullet \textit{function period}\\
\qquad \frac{2\pi }{{{  B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\
\qquad \frac{\pi }{{{  B}}}\ for\ tan(\theta),\ cot(\theta)
\end{array}


so if you notice yours \bf \begin{array}{llll}
3.2cos&\left( \frac{5}{3}\theta \right)+&6.1\\
&\ \uparrow&\uparrow \\
&B&D 
\end{array}

now.. normally the function \bf 3.2cos&\left( \frac{5}{3}\theta \right)
 has a D value of 0, or no vertical shift, and the amplitude and the period simply make the wave taller and thinner, but the midline is still the x-axis

now, with D = 6.1, that moves the midline  up vertically that much

now.. the period, well, B = 5/3, normal period of cosine is 2\pi
so, the new period will be \bf \cfrac{2\pi }{B}\implies \cfrac{2\pi }{\frac{5}{3}}\implies \cfrac{6\pi }{5}

notice the picture below
the vertical shift by the D component, or 6.1, moved the midline to y = 6.1 :)

6 0
3 years ago
Find the product. <br> (y-3)(y-4)=
zubka84 [21]

Answer:

<u>y^2+12-7y</u>

Step-by-step explanation:

(y-3)(y-4)

I will split it up for us

y*y= <u>y^2</u>

-3*y= -3y. \

y*-4= -4y. / <u>-7y</u>

-3*-4= <u>12</u>

<u>y^2+12-7y</u>

7 0
3 years ago
Determine the intercepts of the line.<br> y - 4= 72 – 6)<br> z-intercept:<br> y-intercept:
Goryan [66]
If i am correctthe answer is
y= 70
z=1
4 0
3 years ago
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