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Sergio039 [100]
2 years ago
15

Ashley ate Mexican food 4 out of 7 days on her vacation. If her vacation was 35 days, how many days did she eat Mexican food?

Mathematics
1 answer:
lina2011 [118]2 years ago
8 0

The number of days Ashley ate Mexican food while on vacation is 20 days.

<h3>How many days did Ashley eat mexican food?</h3>

The first step is to determine the fraction of the number of days Ashley atae Mexican food. In order to do this, divide 4 by 7

4/7.

The second step is to multiply 4/7 by 35

4/7 x 35= 20 days

To learn more about multiplication, please check: brainly.com/question/3385014

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The ratio of Michaels's points on an English test to Paloma's points on the same test is 12:11. The ratio of Michaels's points o
diamong [38]

The difference between Palomas and Antons' points on the English test is of 14 points.

<h3>What is Ratio ?</h3>

When two numbers can be written in the form as p:q , they are said to be in Ratio.

It is given that

The ratio of Michaels point to Paloma point is 12 :11

The ratio of Michaels point to Anton's Point is 4:3

Let Paloma's point be x

then Michaels point will be 12x/11

and Anton's points will be

(12x/11 ) / Anton's points = 4 /3

Anton's points = 9x/11

It is given that the sum of the points of the three students is 224

so

x + (12x/11)+ (9x/11) = 224

32x /11 = 224

x = 77

Paloma's points = 77

Anton's Points = 9x/11 = 63

The difference between Palomas and Antons' points on the English test

=77 -63

= 14 points.

To know more about Ratio

brainly.com/question/13419413

#SPJ1

3 0
1 year ago
Resistors for electronic circuits are manufactured on a high-speed automated machine. The machine is set up to produce a large r
Anettt [7]

Answer:

See explanation

Step-by-step explanation:

Given

See attachment for proper presentation of question

Required

Mean and Range

To do this, we simply calculate the mean and the range of each row.

\bar x = \frac{\sum x}{n} ---- mean

Where:

n = 4 ---- number of rows

R = Highest - Lowest --- range

So, we have:

Sample 1

\bar x_1 = \frac{1027+ 994 +977 +994 }{4}

\bar x_1 = 998

R_1 = 1027- 994

R_1 = 33

Sample 2

\bar x_2 = \frac{975 +1013 +999 +1017}{4}

\bar x_2 = 1001

R_2 =  1017 - 975

R_2 = 42

Sample 3

\bar x_3 = \frac{988 +1016 +974 +997}{4}

\bar x_3 = 993.75

R_3 = 1016-974

R_3 = 42

Sample 4

\bar x_4 = \frac{998 +1024 +1006 +1010}{4}

\bar x_4 = 1009.5

R_4 = 1024 -998

R_4 = 26

Sample 5

\bar x_5 = \frac{990 +1012 +990 +1000}{4}

\bar x_5 = 998

R_5 = 1012 -990

R_5 = 22

Sample 6

\bar x_6= \frac{1016 + 998 +1001 +1030}{4}

\bar x_6= 1011.25

R_6= 1030-998

R_6= 32

Sample 7

\bar x_7 = \frac{1000 +983 +979 +971}{4}

\bar x_7 = 983.25

R_7 = 1000-971

R_7 = 29

Sample 8

\bar x_8 = \frac{973 +982 +975 +1030}{4}

\bar x_8 = 990

R_8 = 1030-973

R_8 = 57

Sample 9

\bar x_9 = \frac{992 +1028 +991 +998}{4}

\bar x_9 = 1002.25

R_9 = 1028 -991

R_9 = 37

Sample 10

\bar x_{10} = \frac{997 +1026 +972 +1021}{4}

\bar x_{10} = 1004

R_{10} = 1026 -972

R_{10} = 54

Sample 11

\bar x_{11} = \frac{990 +1021 +1028 +992}{4}

\bar x_{11} = 1007.75

R_{11} = 1028 -990

R_{11} = 38

Sample 12

\bar x_{12} = \frac{1021 +998 +996 +970}{4}

\bar x_{12} = 996.25

R_{12} = 1021 -970

R_{12} = 51

Sample 13

\bar x_{13} = \frac{1027 +993 +996 +996}{4}

\bar x_{13} = 1003

R_{13} =1027 -993

R_{13} =34

Sample 14

\bar x_{14} = \frac{1022 +981 +1014 +983}{4}

\bar x_{14} = 1000

R_{14} = 1022 -981

R_{14} = 41

Sample 15

\bar x_{15} = \frac{977 +993 +986 +983}{4}

\bar x_{15} = 984.75

R_{15} = 993-977

R_{15} = 16

8 0
2 years ago
One watering system needs about three times as long to complete a job as another warning system when both systems operate at the
algol13

Answer:

One watering system requires 36 minutes to complete the job alone while another watering system requires 12 minutes to complete the job alone.

Step-by-step explanation:

Given:

Both the system can complete the job = 9 minutes

We need find the time required by each system to do the job.

Solution:

Let the time required by another watering system to complete the job be 'x' mins.

Now given:

One watering system needs about three times as long to complete a job as another watering system.

Time required by one watering system = 3x

Rate to complete the job by another watering system = \frac{1}{x}\ job/min

Rate to complete the job by One watering system = \frac{1}{3x}\ job/min

Rate at which both can complete the job = \frac{1}{9}\ job/min

So we can say that;

Rate at which both can complete the job is equal to sum of Rate to complete the job by another watering system and Rate to complete the job by One watering system.

framing in equation form we get;

\frac{1}{x}+\frac{1}{3x}=\frac19

Now taking LCM to make the denominator common we get;

\frac{1\times3}{x\times 3}+\frac{1\times1}{3x\times1}=\frac19\\\\\frac{3}{3x}+\frac{1}{3x}=\frac19\\\\\frac{3+1}{3x}=\frac{1}{9}\\\\\frac{4}{3x}=\frac{1}{9}

By Cross multiplication we get;

4\times9 =3x\\\\3x =36

Dividing both side by 3 we get;

\frac{3x}{3}=\frac{36}{3}\\\\x=12\ min

Time required by One watering system = 3x =3\times 12 =36\ min

Hence One watering system requires 36 minutes to complete the job alone while another watering system requires 12 minutes to complete the job alone.

6 0
3 years ago
• What Were the Headlines After a 3 Foot 10 Inch Fortuneteller
pogonyaev
I have no idea what it is lol
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3 years ago
Find two number nearest to 8888888 which are exactly divisible by 2915​
Marysya12 [62]

Step-by-step explanation:

Given problem is to find nearest number,

= 8888888/2915

quotient = 3049

remainder= 1053

Now, 2915-1053 = 1862

8888888+1862 = 8890750

8888888-1053 = 8887835

Two numbers nearest to 8888888 which are exactly divisible by 2915 is 8887835 and 8890750

3 0
2 years ago
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