Help me on dis please
2 answers:
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See the attached figure to better understand the problem
we know that
in the triangle ABC
tan 48°=AB/AC--------> AC=AB/tan48°------> 1200/tan 48°------> 1080.48 ft
in the triangle ABD
tan 33°=AB/AD---------> AD=AB/tan 33°-----> 1200/tan 33°------> 1847.88 ft
<span>the distance between the ships is AD-AC---> 1847.88-1080.48----> 767.4 ft
the answer is
</span>the distance between the ships is 767.4 ft<span>
</span>
we know that
in the triangle ABC
tan 48°=AB/AC--------> AC=AB/tan48°------> 1200/tan 48°------> 1080.48 ft
in the triangle ABD
tan 33°=AB/AD---------> AD=AB/tan 33°-----> 1200/tan 33°------> 1847.88 ft
<span>the distance between the ships is AD-AC---> 1847.88-1080.48----> 767.4 ft
the answer is
</span>the distance between the ships is 767.4 ft<span>
</span>
Answer:
C=14
Step-by-step explanation:
To find the minimum value, graph each of the inequalities. After graphing each inequality, test a point and shade the region that satisfies the inequality. Once all inequalities have been shaded, find the region where they all overlap. The region will be bounded by intersection points. Test each of these points into C=x+3y. The least value for C is the minimum.
(14,0) (0,17.5) (3.08,3.64)
C=14+3(0) C=0+3(17.5) C=3.08 + 3(3.64)
C=14 C=52.5 C=14
