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Doss [256]
3 years ago
15

kevin scored 11 points in his last basketball game. if kevin made two more free throws (one point each) then two-point shots, ho

w many of each shot did he make? choose the graph that best depicts this problem.
Mathematics
1 answer:
nataly862011 [7]3 years ago
6 0

Answer:

Kevin made 5 free throws and 3 two-point shots.

Step-by-step explanation:

Given that Kevin scored 11 points in his last basketball game, to determine if Kevin made two more free throws (one point each) than two-point shots how many of each shot did he make, the following calculation must be performed:

11 x 1 + 0 x 2 = 11

6 x 1 + 4 x 2 = 14

5 x 1 + 3 x 2 = 11

Therefore, Kevin made 5 free throws and 3 two-point shots.

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PLEASE HELP QUICK!! Repost because typos | 100 POINTS
Oksi-84 [34.3K]

Answer:

Step-by-step explanation:

Well you have to first look at the chart to see if it fits what Ariel claimed.

There is actually a higher percent of students with no siblings that have pets if you look at the total for students with no siblings. If you look at the number though 45>39. Also her claim is not justified because the percentage is lower for students with siblings. Thanks for the 50 points ;) If you have any questions just ask

4 0
3 years ago
In general, the point ___is on the graph of the function f(x) = a×b^x.​
Alexxandr [17]

Answer:

Option A (0,a)

Step-by-step explanation:

we know that

f(x)=a(b^{x})

Is a exponential function

where

a is the initial value

b is the base

Remember that

The initial value is the value of the function when the value of x is equal to zero (y-intercept)

therefore

For x=0

f(0)=a(b^{0})

f(0)=a(1)=a

The y-intercept is the point (0,a)

6 0
4 years ago
Read 2 more answers
A bucket that weighs 3 lb and a rope of negligible weight are used to draw water from a well that is 90 ft deep. The bucket is f
Lisa [10]

Answer:

a) Lim(0-inf)  Work = (36 - 0.1*xi )*dx

b) Work = integral( (36 - 0.1*xi ) ).dx

c) Work = 2835 lb-ft

Step-by-step explanation:

Given:

- The weight of the bucket W = 3 lb

- The depth of the well d = 90 ft

- Rate of pull = 2.5 ft/s

- water flow out at a rate of = 0.25 lb/s

Find:

A. Show how to approximate the required work by a Riemann sum (let x be the height in feet above the bottom of the well. Enter xi∗as xi)

B. Express the Integral

C. Evaluate the integral

Solution:

A.

- At time t the bucket is xi = 2.5*t ft above its original depth of 90 ft but now it hold only (36 - 0.25*t) lb of water at an instantaneous time t.

- In terms of distance the bucket holds:

                           ( 36 - 0.25*(xi/2.5)) = (36 - 0.1*xi )

- Moving this constant amount of water through distance dx, we have:

                            Work = (36 - 0.1*xi )*dx

B.

The integral for the work done is:

                           Work = integral( (36 - 0.1*xi ) ).dx

Where the limits are 0 < x < 90.

C.

- Evaluate the integral as follows:

                           Work = (36xi - 0.05*xi^2 )

- Evaluate limits:

                           Work = (36*90 - 0.05*90^2 )  

                            Work = 2835 lb-ft

8 0
3 years ago
Find the value of n .<br> 6/n = 24/28<br> y = ___.
il63 [147K]

Answer:

n=7

Step-by-step explanation:

Cross multiply, isolate the variable, and divide by the coefficient to solve.

\frac{6}{n}=\frac{24}{28} \\ \\ 24n=168 \\ \\ n=7

Plug back in to check.

\frac{6}{7}=0.857142857 \\ \\ \frac{24}{28} =0.857142857

5 0
4 years ago
7 1/2 divided by 3/4
murzikaleks [220]
Your answer is 10 because I just changed them to decimals.... 7.5 divided by .75 = 10
5 0
3 years ago
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