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Sindrei [870]
3 years ago
14

A dealer sold 500 tennis racquets some were sold at $20 each and the rest were sold at $45 each. The total receipts from these s

ales were $20000 . How many racquets did he sell at $20 each
Mathematics
2 answers:
arlik [135]3 years ago
8 0

Answer:

He sold 100 rackets for $ 20

Step-by-step explanation:

To start, we have to make 2 equations, one that represents the number of rackets and the other the money

x + y = 500

x * 20 + y * 45 = 20000

we clear x in the first equation

x + y = 500

x = 500 - y

we replace x in the second equation with (500 - y)

x * 20 + y * 45 = 20000

(500 - y) * 20 + y * 45 = 20000

10000 - 20y + 45y = 20000

-20y + 45y = 20000 - 10000

25y = 10000

y = 10000/25

y = 400

we replace x in the first equation with the value obtained

x = 500 - y

x = 500 - 400

x = 100

He sold 100 rackets for $ 20

OverLord2011 [107]3 years ago
7 0

Answer: they sold 100 racquets at $20 each.

Step-by-step explanation:

Let x represent the number of tennis racquets that were sold at $20 each.

Let y represent the number of tennis racquets that were sold at $45 each.

A dealer sold 500 tennis racquets some were sold at $20 each and the rest were sold at $45 each. It means that

x + y = 500

The total receipts from these sales were $20000. This means that

20x + 45y = 20000- - - - - - - - - -1

Substituting x = 500 - y into equation 1, it becomes

20(500 - y) + 45y = 20000

10000 - 20y + 45y = 20000

- 20y + 45y = 20000 - 10000

25y = 10000

y = 10000/25

y = 400

x = 500 - 400

x = 100

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