The <em>correct answers</em> are:
A) Both can be solved by graphing;
C) Both can be solved by substitution; and
D) Both have solutions at the points of intersection.
Explanation:
Just as a system of linear equations can be solved by graphing, a system of quadratic equations can as well. We graph both equations. We then look for the intersection points of the graphs; these intersection points will be the solutions to the system.
We can also solve the system by substitution. If we can get one variable isolated, we can substitute this into the other equation to solve.
Answer:
B
Step-by-step explanation:
6n - 2(4n + 7) + 4= -2 firstly you open the bracket
6n - 8n - 14 + 2 = -2 then you collect the like terms
6n - 8n= -2 + 14 - 4 then add and subtract and divide by the coefficient
-2n= 12 - 4
-2n = 8
= n = 8 ÷ -2
n = -4
Answer:
s for length of either equal side
b for the unequal side
b=-2+2*(s+s) and 2s+b=40
b=2*2s-2
b=4s-2
2s+4s-2=40
6s-2=40
6s=42
s=7
b=4*7-2
b=28-2
b=26
Answer:
C. 55°
Step-by-step explanation:
Note the total measurement of angles for a triangle. The total measurement of all angles in a triangle = 180°
Note that m∠C is a right angle (as shown through the square), and that right angles = 90°
Subtract to find the measurement of the unknown angle (∠B)
∠B = 180 - (∠A + ∠C)
∠B = 180 - (35 + 90)
Simplify. Combine like terms. First, add (solve parenthesis), then subtract.
∠B = 180 - (125)
∠B = 55
m∠B = C. 55°
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5pi/12 radians
The arc measure is 75, so theta must also be the same. if theta is 75, and 75 in radians is 5pi/12 radians, then the answer is that.