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yan [13]
3 years ago
5

How many dollars does 3 bottles of water cost ?

Mathematics
1 answer:
Zinaida [17]3 years ago
3 0

Answer:

$7.5

Step-by-step explanation:

if we set up the proportion \frac{10}{4} =\frac{x}{3}   with cost on top and water bottles on bottom, we can divide  10/4 too get 2.5, which we can then multiply by 3 to get our x value, 7.5.

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In a study of
o-na [289]
We know that:
Mean = 82 mm and SD = 10 mm ( standard deviation )
82 - 3 * SD = 82 - 3 * 10 = 82 - 30 = 52 mm
82 + 3 * SD = 82 + 3 * 10 = 82 + 30 = 112 mm
Population between 52 and 112 mm is within +/- 3 standard deviations from the mean.
By the 66- 95 - 99.7 % rule it is: 99.7% of the test group.
0.977 * 500 = 498.5
Answer:
99.7 % of the test group have a diastolic pressure between 52 and 112 mm, or 498 men. 
5 0
3 years ago
Triangle MNP is similar to triangle QRS. Which sides have the same slope?
lilavasa [31]

Answer:

The corresponding sides have the same slope so the answer is QR and MN, SR and PN and MP and QS. Hope this helps!

7 0
3 years ago
How many triangles exist with the given side lengths?<br><br> 12 in, 15 in, 18 in
aniked [119]
One because the law of consines works on it
5 0
2 years ago
Read 2 more answers
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kenny6666 [7]

Answer:64

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
A data includes 108 body temperature od healthy adult humans having a mean of 98.2 f and a standard deviation of .64f. Contruct
leonid [27]

Answer: ( 98.04f, 98.40f ), it is not accepted

Step-by-step explanation: the question is suggesting we construct a 99% confidence interval for mean body temperature.

The formulae for Constructing a 99% confidence interval is given below as

u = x + Zα/2 × (s/√n)........... For the upper limit

u = x - Zα/2 × (s/√n)........... For the lower limit

Where u = population mean

x = sample mean = 98.2

s = sample standard deviation = 0.64

n = sample size = 108.

Zα/2 = critical value for a 2 tailed test performed at a 1% level of significance ( 100% - 99%) = 2.58

We are making use of our z test because sample size is greater than 30 ( n = 108).

By substituting the parameters, we have that

For upper limit

u = x + Zα/2 × (s/√n)

u = 98.2 + 2.58 ( 0.64/√108)

u = 98.2 + 2.58 ( 0.0616)

u = 98.2 + 0.1589

u = 98.4

For lower limit

u = x - Zα/2 × (s/√n)

u = 98.2 - 2.58 ( 0.64/√108)

u = 98.2 - 2.58 ( 0.0616)

u = 98.2 - 0.1589

u = 98.04.

Hence the 99% confidence interval for mean temperature of human is ( 98.04f, 98.40f )

Using 98.6f as the average mean body temperature is wrong because it is out of the confidence interval calculated above.

Our confidence interval states that at 99% confidence interval, an average human temperature should be at least 98.04f and at most 98.40f.

98.6f is out of the range.

4 0
3 years ago
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