Let's start off with a simple y-intercept form.
y=mx + b
b represents the y intercept so we can substitute it with 2.
y = mx + 2
the point we are given, (1,1) is really just an x and y value. We can also substitute this into the equation.
y = x + 2
Now that we have some type of equation, we can convert it to the form shown in the answer choices by subtracting y from both sides.
0 = x - y + 2
Hope this helps!
Answer:
30 m/s
Step-by-step explanation:
Let's say the distance from the first car to the intersection is x, and the distance from the second car to the intersection is y.
The distance between the cars can be found with Pythagorean theorem:
d² = x² + y²
Taking derivative with respect to time:
2d dd/dt = 2x dx/dt + 2y dy/dt
d dd/dt = x dx/dt + y dy/dt
We know that x = 200, dx/dt = -25, y = 150, and dy/dt = -50/3.
To find dd/dt, we still need to find d.
d² = x² + y²
d² = (200)² + (150)²
d = 250
Plugging everything in:
250 dd/dt = (200) (-25) + (150) (-50/3)
dd/dt = -30
The cars are approaching each other at a rate of 30 m/s at that instant.
14.81 radians/second
Step-by-step explanation:
