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AURORKA [14]
3 years ago
6

PLS HELP 20 POINTS- will give brainliest

Mathematics
2 answers:
SVEN [57.7K]3 years ago
8 0

Answer:

I thought I answered this before

-2

Step-by-step explanation:

Rus_ich [418]3 years ago
6 0

Answer:

-2

Step-by-step explanation:

im taking  algebra 2 and this was a question

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4. will give brainliest
saul85 [17]

The equation of the ellipse in <em>standard</em> form is (x + 3)² / 100 + (y - 2)² / 64 = 1. (Correct choice: B)

<h3>What is the equation of the ellipse associated with the coordinates of the foci?</h3>

By <em>analytical</em> geometry we know that foci are along the <em>major</em> axis of ellipses and beside the statement we find that such axis is parallel to the x-axis of Cartesian plane. Then, the <em>standard</em> form of the equation of the ellipse is of the following form:

(x - h)² / a² + (y - k)² / b² = 1, where a > b     (1)

Where:

  • a - Length of the major semiaxis.
  • b - Length of the minor semiaxis.

Now, we proceed to find the vertex and the lengths of the semiaxes:

a = 10 units.

b = 8 units.

Vertex

V(x, y) = 0.5 · F₁(x, y) + 0.5 · F₂(x, y)

V(x, y) = 0.5 · (3, 2) + 0.5 · (- 9, 2)

V(x, y) = (1.5, 1) + (- 4.5, 1)

V(x, y) = (- 3, 2)

The equation of the ellipse in <em>standard</em> form is (x + 3)² / 100 + (y - 2)² / 64 = 1. (Correct choice: B)

To learn more on ellipses: brainly.com/question/14281133

#SPJ1

8 0
2 years ago
Which table represents la linear function?
lions [1.4K]

Answer:

I believe it would be the last table.

Step-by-step explanation:

A linear function has an equation of y=Mx+b where y and x are the variables but m (the slope) and b are constants. The slope for the last table is -8 as the y values are decreasing by 8 every time you move forward one in the x axis. None of the other tables have a constant slope which means they don’t have straight lines when you graph them. Therefore, the last table would have to be the only one representing a linear function

3 0
3 years ago
What is the diffrenc e between a 1 1/4 and 3/8
ycow [4]

Answer:

7/8

Step-by-step explanation:

4 0
3 years ago
What are the missing sides and angles of this triangle? What is the area?
Butoxors [25]
This does not appear to be a right triangle.  However, we know 2 sides and the included angle, so can find the unknown side length.  Let x represent this length.  Then:

x^2 = (9 m)^2 + (12 m)^2 - 2(9m)(12 m)*cos 30 degrees, or

x^2 = 81 + 144 - 216(sqrt(3) / 2).  Please solve for x^2 and then solve the result for x, making sure to choose the positive value.  The result will be the length of the side opposite the 30 degree angle.

With 1 of 3 angles known, and 3 of 3 sides known, you can use the Law of Sines to find the other two angles.  As a reminder, the Law of Sines looks like this:

   a            b              c
-------- = --------- = ----------
sin A       sin B       sin C.

You can give the 30-deg angle any name you want; then a, the length of the side opposite the 30-deg angle, which you have just found.  And so on.  
4 0
3 years ago
Suppose that X has a Poisson distribution with a mean of 64. Approximate the following probabilities. Round the answers to 4 dec
o-na [289]

Answer:

(a) The probability of the event (<em>X</em> > 84) is 0.007.

(b) The probability of the event (<em>X</em> < 64) is 0.483.

Step-by-step explanation:

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em> = 64.

The probability mass function of a Poisson distribution is:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0, 1, 2, ...

(a)

Compute the probability of the event (<em>X</em> > 84) as follows:

P (X > 84) = 1 - P (X ≤ 84)

                =1-\sum _{x=0}^{x=84}\frac{e^{-64}(64)^{x}}{x!}\\=1-[e^{-64}\sum _{x=0}^{x=84}\frac{(64)^{x}}{x!}]\\=1-[e^{-64}[\frac{(64)^{0}}{0!}+\frac{(64)^{1}}{1!}+\frac{(64)^{2}}{2!}+...+\frac{(64)^{84}}{84!}]]\\=1-0.99308\\=0.00692\\\approx0.007

Thus, the probability of the event (<em>X</em> > 84) is 0.007.

(b)

Compute the probability of the event (<em>X</em> < 64) as follows:

P (X < 64) = P (X = 0) + P (X = 1) + P (X = 2) + ... + P (X = 63)

                =\sum _{x=0}^{x=63}\frac{e^{-64}(64)^{x}}{x!}\\=e^{-64}\sum _{x=0}^{x=63}\frac{(64)^{x}}{x!}\\=e^{-64}[\frac{(64)^{0}}{0!}+\frac{(64)^{1}}{1!}+\frac{(64)^{2}}{2!}+...+\frac{(64)^{63}}{63!}]\\=0.48338\\\approx0.483

Thus, the probability of the event (<em>X</em> < 64) is 0.483.

5 0
3 years ago
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