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2 years ago

X=(-2x)+6 help meeeee

Mathematics

1 answer:

vitfil [10]2 years ago

6 0

Answer:

x = 2

Step-by-step explanation:

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Find the domain and range of: {(-2,0), (-1,1), (0,2),(1,3)}

Harman [31]

Answer: domain: {-2, -1, 0, 1}

range: {0, 1, 2, 3}

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2 years ago

Consider the diagram.

Dima020 [189]

Answer:

AB = 9

Step-by-step explanation:

Given that line, l is a perpendicular bisector of line segment AC. It intersects line segment AC at point B.

So, we can conclude that AB = BC ............ (1)

Also given that the length of line segment BC is 9.

Now, from equation (1) we can say that, AB = 9.

Therefore, the length of segment AB is 9. (Answer)

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3 years ago

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Bumek [7]

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3 years ago

Translate<br> Solve the equation.<br> 3m= 5(m + 3)-3<br> HELP

kvasek [131]

Answer:

m = -6

Step-by-step explanation:

3m= 5(m + 3)-3

Distribute

3m = 5m +15 -3

Combine like terms

3m = 5m +12

Subtract 5m

3m-5m = 5m+12-5m

-2m = 12

Divide by -2

-2m/-2 = 12/-2

m = -6

7 0

3 years ago

OOOO

lbvjy [14]

Step-by-step explanation:

Given bi-quadratic equation is:

$x^4+95x^2 -500=0$

Substituting $x^2=a,$ given bi-quadratic equation reduces in the form of following quadratic equation:

$a^2 +95a -500=0\\$

Let us factorize the above quadratic equation:

$a^2 +95a -500=0\\\therefore\: a^2 +100a -5a-500=0\\\therefore\: a(a +100) -5(a+100)=0\\\therefore\: (a +100)(a -5)=0\\\therefore\: (a +100)=0\:\: or \:\: (a -5)=0\\\therefore\: a = - 100\:\: or \:\: a = 5\\\\CASE\: (1)\:\\When\: a = - 100 \implies x^2 = - 100\\\therefore x=\pm \sqrt{-100}\\$

Since square root of a negative number cannot be found, so:

$x \neq \pm \sqrt{-100}\\$

$CASE\: (2)\:\\When\: a =5 \implies x^2 =5\\\therefore x=\pm \sqrt{5}\\$

3 0

2 years ago