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2 years ago

Can someone help me out with my math homework my grades are bad

Mathematics

1 answer:

Blizzard [7]2 years ago

5 0

Answer:

In first box, it’s 5

and then it’s 6/10

Step-by-step explanation:

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How do you represent real-world problems involving ratios and rates with tables and graphs?

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Find the percentage of people with that problem or the percentage of it happening and put it in a circle graph like for example some people believe that certain vehicles shouldn't be allowed cause they cause population so i will put that percent in a circle graph and percent of people who think opposite

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3 years ago

What is the mean of the data set?

svetoff [14.1K]

B) 12.75
Just add them all together
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The devide the anser by the ammount of numbers you added together
153÷12=12.75

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2 years ago

Read 2 more answers

Write an equation for the following graph.

romanna [79]

Y=Ix+1I-3
the absolute value of( x+1) minus 3

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3 years ago

Jacob is asked to solve the follow problem: "Kayla is 9 years older than twice Hannah’s age. If the difference in their ages is

tatiyna

Answer:

Step-by-step explanation:

k = 2h+9

h+16=k

h+16=2h+9

-h = -7

h = 7

hannah is 7 and kayla is 23

jacob is wrong because if u do 16*2+7 it’s 39 and 39-16 does not equal 16

6 0

2 years ago

2. Given a quadrilateral with vertices (−1, 3), (1, 5), (5, 1), and (3,−1):

zlopas [31]

<h2>Explanation:</h2>

In every rectangle, the two diagonals have the same length. If a quadrilateral's diagonals have the same length, that doesn't mean it has to be a rectangle, but if a parallelogram's diagonals have the same length, then it's definitely a rectangle.

So first of all, let's prove this is a parallelogram. The basic definition of a parallelogram is that it is a quadrilateral where both pairs of opposite sides are parallel.

So let's name the vertices as:

$A(-1,3) \\ \\ B(1,5) \\ \\ C(5,1) \\ \\ D(3,-1)$

First pair of opposite sides:

<u>Slope:</u>

$\text{For AB}: \\ \\ m=\frac{5-3}{1-(-1)}=1 \\ \\ \\ \text{For CD}: \\ \\ m=\frac{1-(-1)}{5-3}=1 \\ \\ \\ \text{So AB and CD are parallel}$

Second pair of opposite sides:

<u>Slope:</u>

$\text{For BC}: \\ \\ m=\frac{1-5}{5-1}=-1 \\ \\ \\ \text{For AD}: \\ \\ m=\frac{-1-3}{3-(-1)}=-1 \\ \\ \\ \text{So BC and AD are parallel}$

So in fact this is a parallelogram. The other thing we need to prove is that the diagonals measure the same. Using distance formula:

$d=\sqrt{(y_{2}-y_{1})^2+(x_{2}-x_{1})^2} \\ \\ \\ Diagonal \ BD: \\ \\ d=\sqrt{(5-(-1))^2+(1-3)^2}=2\sqrt{10} \\ \\ \\ Diagonal \ AC: \\ \\ d=\sqrt{(3-1)^2+(-5-1)^2}=2\sqrt{10} \\ \\ \\$

So the diagonals measure the same, therefore this is a rectangle.

5 0

3 years ago