<u><em>The additive identity property </em></u>. . . is being used here because no matter what the value is, whenever you add zero (0) to it, you'll always get the value your started with.
9514 1404 393
Answer:
13 in by 51 in
Step-by-step explanation:
The area is the product of the dimensions, so is ...
663 = x(4x -1)
4x^2 -x -663 = 0 . . . . . . subtract 663 to put in standard form
Using the quadratic formula, we can find the solutions.
x = (-(-1) ±√((-1)^2 -4(4)(-663)))/(2(4))
x = (1 ± √10609)/8 = (1 ±103)/8
Only the positive solution is of any use in this problem, so ...
x = 104/8 = 13
4x-1 = 4(13)-1 = 51
The dimensions of the rectangle are 13 inches by 51 inches.
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I find it easiest to solve these using a graphing calculator.
Answer:
D. None of the choices are correct.
Step-by-step explanation:
If <em>B</em> is the midpoint of AC, then that means that AB is congruent to BC. Because this is true, you can set 8x + 4 and 10x - 8 equal.
8x + 4 = 10x - 8
Now just solve for x. Subtract 8x from both sides and add 8 to both sides.
4 = 2x - 8
12 = 2x
Then divide by 2.
6 = x
Another way to do this problem is to set up the same equation, but instead of solving it, plug in answer choices A, B, and C independently of each other. Then simplify to see if those are right. You'll find out that none of them are.
Answer:
(2 x x)^2 - (3 x y)^2
Step-by-step explanation:
Hope that helps sorry if it dosen't.
