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nexus9112 [7]
3 years ago
6

Joseph earns $15 for every law he mows. Is the amount of money he earns professional to the number of launch he mows? Make a tab

le to help you did if I the type of relationship
Mathematics
1 answer:
yKpoI14uk [10]3 years ago
3 0

launch?

I need this written better to understand.

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The algebraic expression 6x - 4 can
sveticcg [70]

Answer:

Six times a number x less than four less than six

8 0
3 years ago
The seventh grade students are having an end-of-year party in the school
Ahat [919]

The complete statement is:

  • Determine the number of tables by dividing 754 by 6
  • If there is a remainder, the answer will need to be rounded.
  • There is a remainder, so 126 tables are needed.

<h3>How to determine the number of tables?</h3>

The given parameters are:

Students = 754

Student per table = 6

The number of tables is calculated as:

Table = Students / Student per table

This gives

Table = 754/6

Evaluate the quotient

Table = 125.7

Approximate

Table = 126

Hence, the complete statement is:

Determine the number of tables by dividing 754 by 6

If there is a remainder, the answer will need to be rounded.

There is a remainder, so 126 tables are needed.

Read more about quotient at:

brainly.com/question/629998

#SPJ1

6 0
1 year ago
The value of a treadmill bought new for $1000 decreases 5% each year. Use a graph to predict the value of the treadmill in 5 yea
Georgia [21]
The formula is
V (t)=V0 (1-r)^t
V (t)?
V0 1000
R 0.05
T 5 years

V (5)=1,000×(1−0.05)^(5)=773.78
6 0
3 years ago
A piece of wire 23 m long is cut into two pieces. One piece is bent into a square and the other is bent into an equilateral tria
AURORKA [14]

Answer:

For maximum area, all of the wire should be used to construct the square.

The minimum total area is obtained when length of the wire is 10m

Step-by-step explanation:

For maximum,  we use the whole length

For minimum,

supposed the x length was used for the square,

the length of the side of the square = x/4m

Area = \frac{x^{2} }{16}

For the equilateral triangle, the length of the side =  \frac{23 - x}{3}

Area = \frac{\sqrt{3} }{4}  a^{2}  = \frac{\sqrt{3} }{4} (\frac{23 - x}{3} )^{2}

Total Area = \frac{x^{2} }{16}  + \frac{\sqrt{3} }{36} (23-x)^{2}

\frac{dA}{dx}  = \frac{x}{8}  -  \frac{\sqrt{3} }{18} (23 - x)\\

\frac{d^{2}A }{dx^{2} }  = \frac{1}{8}  + \frac{\sqrt{3} }{18}  > 0, therefore it is minimum

\frac{dA}{dx}  = 0 \\\\

\frac{x}{8}  -  \frac{\sqrt{3} }{18} (23 - x) = 0\\

x = 10.00m

3 0
3 years ago
Read 2 more answers
Roll a dice. Chance of it landing on a 6 is ? In ?
ohaa [14]
It is a 1 to 6 ratio
4 0
4 years ago
Read 2 more answers
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