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3 years ago

Please help I’m not good at triangle angles

Mathematics

1 answer:

wlad13 [49]3 years ago

6 0

Answer:

Step-by-step explanation:

Two of the angles are just numbers and you add them.

The third is a term and you add it along with the other two.

The total is always 180 for a triangle.

80 + 58 + 5x - 3 = 180

138 + 5x - 3 = 180 Combine on the left

135 + 5x = 180 Subtract 135 from both sides

5x = 180 - 135 Combine the right

5x = 45 Divide by 5

x = 9

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Instructions: Given the following image of two parallel lines cut by a transversal, find the value of x.

mash [69]

Answer:

First, these angles are alternate interior angles.

$10x - 5 = 9x + 1$

$x = 6$

Step-by-step explanation:

(10x - 5)° and (9x + 1)° are alternate interior angles. Thus, they are congruent to each other.

Thus, to find x, we will set each angle equal to the other.

$10x - 5 = 9x + 1$

Solve for x. Collect like terms

$10x - 9x = 5 + 1$

$x = 6$

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3 years ago

a. What is the area and circumference of circle P? Explain how you calculated this answer. b. If the arc measure of arc COD is 1

Vikki [24]

Answer:

a) 9*π or approx 28.26

b) ∡CRB=100°

Step-by-step explanation:

As known for secants crossing each other inside the circle is coorect the following:

BR*RD=AR*RC

=> 3*RD=4*4.5

RD=6

The diameter of the circle with center P is BD=BR+RD=3+6=9

So the radius of the circle is D/2=9/2=4.5

As known the circumference of any circle can be calculated as

C=2*π*r , where r is the circle's radius

So C=2*4.5*π=9*π= approx 3.14*9=28.26

b) ∡CRB=∡ARD= (arcBC+arcAD), where arcBC and arcAD smaller arcs

BD is the circle's diameter, so arc BD=180°

So arcBC=180°-arcCOD=180°-100°=80°

Similarly arcBD=180°

arcAD=180°-arcBSA=180°-60°=120°

∡CRB= (80°+120°)/2=100°

5 0

3 years ago

Thetime(inhours)requiredtorepairamachineis an exponentially distributed random variable with parameter λ = 1 . What is 2 (a) the

mihalych1998 [28]

Answer:

a) 0.1353

b) 0.3679

Step-by-step explanation:

Let's start by defining the random variable T.

T : ''The time (in hours) required to repair a machine''

T ~ exp (λ)

T ~ exp (1)

The probability density function for the exponential distribution is

(In the equation I replaced λ = L)

$f(x)=Le^{-Lx}$

With L > 0 and x ≥ 0

In this exercise λ = 1 ⇒

$f(x)=e^{-x}$

For a)

$P(T>2)$

$P(T>2)=1-P(T\leq 2)$

$P(T>2)=1-\int\limits^2_0 {e^{-x} } \, dx$

$P(T>2)=1-(-e^{-2}+1)$

$P(T>2)=e^{-2}=0.1353$

For b)

$P(T\geq 10/T>9)$

The event (T ≥ 10 / T > 9) is equivalent to the event T ≥ 1 so they have the same probability of occur

$P(T\geq 10/T>9)=P(T\geq 1)$

$P(T\geq 1)=1-P(T$

$P(T\geq 1)=1-(-e^{-1}+1)=e^{-1}=0.3679$

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3 years ago

On a certain day the temperature changed a rate of -3 degrees Fahrenheit per hour how long did it take for the temperature to ch

zhannawk [14.2K]

Answer: is 11 hours.

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3 years ago

The school's basketball team lost 4 times as many games as they won. They also tied 5 fewer games than they won.

jekas [21]

Let w won games, t tied games, s lose games

s=4w

t=w-5

s+t+w=43

4w+(w-5)+w=43

6w=48

w=7

s=4*7=21 games lost

7 0

3 years ago