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Ksju [112]
3 years ago
15

Multiply 546.1 × 0.52 = ____

Mathematics
1 answer:
Valentin [98]3 years ago
7 0
<h2>Answer:</h2><h2>283.972 is your final answer</h2><h2></h2><h2>Hope this helps!!! <3</h2>

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Answer:

329 degrees F

Step-by-step explanation:

If you plug in your known variables into the calculator, you would get the answer 329 for <em>F</em>. You plug in 165 as <em>C </em>in the equation to find your answer.

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Step-by-step explanation:

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The projected rate of increase in enrollment at a new branch of the UT-system is estimated by E ′ (t) = 12000(t + 9)−3/2 where E
nexus9112 [7]

Answer:

The projected enrollment is \lim_{t \to \infty} E(t)=10,000

Step-by-step explanation:

Consider the provided projected rate.

E'(t) = 12000(t + 9)^{\frac{-3}{2}}

Integrate the above function.

E(t) =\int 12000(t + 9)^{\frac{-3}{2}}dt

E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+c

The initial enrollment is 2000, that means at t=0 the value of E(t)=2000.

2000=-\frac{24000}{\left(0+9\right)^{\frac{1}{2}}}+c

2000=-\frac{24000}{3}+c

2000=-8000+c

c=10,000

Therefore, E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000

Now we need to find \lim_{t \to \infty} E(t)

\lim_{t \to \infty} E(t)=-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000

\lim_{t \to \infty} E(t)=10,000

Hence, the projected enrollment is \lim_{t \to \infty} E(t)=10,000

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3 years ago
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Answer:

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So, the given equation has solution for which LHS=RHS=0.

Step-by-step explanation:

The answer to the equation is 2

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Point E is correct answer
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