Nesesito ayuda cúanto es (-14)+(+14)=

Mathematics

1 answer:

galina1969 [7]2 years ago

4 0

Answer:

Step-by-step explanation:

-14 + (+14)

-14 + 14

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iren2701 [21]

$\large\begin{array}{l} \textsf{Find the domais of the rational function:}\\\\ \mathsf{C(x)=\dfrac{x-5}{x^2-25}}\\\\\\ \textsf{Denominators can't be zero:}\\\\ \mathsf{x^2-25\ne 0}\\\\ \mathsf{x^2\ne 25}\\\\ \begin{array}{rcl} \boxed{\begin{array}{rcl}\mathsf{x\ne -5}&~\textsf{ and }~&\mathsf{x\ne 5}\end{array}} \end{array} \end{array}$

$\large\begin{array}{l} \textsf{So the domain of C is}\\\\ \mathsf{D_C=\{x\in\mathbb{R}:~~x\ne -5~~and~~x\ne 5\}}\\\\\\ \textsf{or using a more compact form}\\\\ \mathsf{D_C=\mathbb{R}\setminus\{-5,\,5\}}\\\\\\ \textsf{or in interval notation}\\\\ \mathsf{D_C=\left]-\infty,\,-5\right[\,\cup\,\left]-5,\,5\right[\,\cup\,\left]5,\,+\infty\right[\,.} \end{array}$

$\large\textsf{So pick up the one you prefer. They're equivalent ways}\\\textsf{to represent the domain.}$

If you're having problems understanding this answer, try seeing it through your browser: brainly.com/question/2184171

$\large\textsf{I hope this helps. :-)}$

Tags: domain rational function fraction denominator restriction algebra

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kramer

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