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3 years ago

A population numbers 15,500 and grows at 3.75% per year. Write an exponential model for the growth of this population.

Mathematics

1 answer:

krek1111 [17]3 years ago

4 0

Answer: $f(x)=15500(1.0375)^x$

Step-by-step explanation:

The exponential model for growth is given by :-

$f(x)=A(1+r)^x$ , where A = initial value , r = growth rate (in decimal), x = time (in years).

Given: A= 15,500 r= 3.75% = 0.0375

The exponential model for the growth of this population will be :

$f(x)=15500(1+0.0375)^x\\\\\Rightarrow\ f(x)=15500(1.0375)^x$

hence, the required model: $f(x)=15500(1.0375)^x$

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Natalija [7]

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3 years ago

What is the value of the angle marked with x?

morpeh [17]

Given:

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To find:

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Solution:

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3 years ago

The box is 450 square. The length is 10 inches and the width is 5 inches. What is the height of the box

natali 33 [55]

Answer:

9 inches

Step-by-step explanation:

I assume you mean the volume of the box is 450.

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2 years ago

There are three different hoses used to fill a pool: hose x, hose y, and hose z. Hose x can fill the pool in a days, hose y in b

WARRIOR [948]

Answer:

C) I and III only

Step-by-step explanation:

Let full pool is denoted by O

Days Hose x takes to fill pool O = a

Pool filled in one day x = O/a

Days Hose y takes to fill pool O = b

Pool filled in one day y = O/b

Days Hose z takes to fill pool O = c

Pool filled in one day z = O/c

It is given that

a>b>c

$a>b>c>d\\\implies x$

Days if if x+y+z fill the pool together = d

1 day if x+y+z fill the pool together $=O(\frac{1}{a}+\frac{1}{b}+\frac{1}{c})=\frac{O}{d}---(1)$

I) d < c

d are days when hose x, y, z are used together where as c are days when only z is used so number of days when three hoses are used together must be less than c when only z hose is used. So d < c

III) $\frac{c}{3}$