Let F(x) = x^2 + 2x -8
Adding 1 and - 1 at equation
F(x) = x^2 + 2x + 1 - 1 -8
Rewrinting the first 1 = 1^2
F(x) = x^2 + 2x + 1^2 - 1 - 8
Now look:
x^2 + 2x + 1^2 = ( x + 1)^2
Then,
F(x) = (x + 1)^2 -1 -8
F(x) = (x + 1)^2 -9
This is the answer !
If us to want.
(x + 1)^2 -9 = ( x+1)^2 - 3^2
= ( x+ 1 -3).(x +1 +3)
= ( x - 2).(x +4)
The easiest thing to find in a table showing a linear relationship is the slope. If the x is increasing by one each and every time (or cell because we are talking about tables), then the difference between each y value is the slope. Also, if you are lucky enough to have that sort of table, you can easily find the y-intercept by looking at the y value that is next to the x value of 0. Otherwise, work backward to find the y-intercept. For every x value you go down to try and get to 0, minus the y values also by the slope.
It will be 5 because 4^2+3^2= 16+9=25 and then square root of 25=5
<h3>(-3j²k³)²(2j²k)³</h3>
(-3j²k³)²(2j²k)³ = <em>When a power is raised to a power the exponents have to be multiplied.</em>
= (-3²j⁽²*²⁾k⁽³*²⁾)(2³j⁽²*³⁾k³) = <em>We can take out the constants</em>
= (9)(8)(j⁴k⁶)(j⁶k³) = <em>We can group the same variables</em>
= 72(j⁴j⁶)(k⁶k³) = <em>When multiplying two powers that have the same base, you have to add the exponents.</em>
= 72 j⁽⁴⁺⁶⁾k⁽⁶⁺³⁾ = 72j¹⁰k⁹
Answer = 72j¹⁰k⁹
Hope this helps!
