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luda_lava [24]
3 years ago
6

When balls roll out of sight, do they disappear or play hopscotch? Or maybe……. Just maybe…… they play hide and seek. I’m not rea

lly sure.
Physics
1 answer:
Anuta_ua [19.1K]3 years ago
3 0

Answer:

they play hide and seek with me and im always the seeker U-U

Explanation:

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the book has a mass of 2.5 kg. What net force must act on the book to mak it accelerate to the left at a rate of 7.0m/s2?
Reil [10]

Answer:

17.5 N

Explanation:

<h2>Given :</h2>

  • Mass (m) = 2.5 kg
  • Acceleration (a) = 7.0 m/s²

<h2>To calculate :</h2>

  • Force exerted (F)

<h2>Calculation :</h2>

<h3>• F = ma</h3>

→ F = (2.5 × 7.0) N

→ F = 25/10 × 7 N

→ F = 5/2 × 7 N

→ F = (5 × 7)/2 N

→ F = 35/2 N

→ <u>F</u><u> </u><u>=</u><u> </u><u>1</u><u>7</u><u>.</u><u>5</u><u> </u><u>N</u><u> </u><u>towards</u><u> </u><u>left</u>

Hence, 17.5 N of net force must act on the book to make it accelerate to the left.

5 0
2 years ago
Explain the difference between Longitudinal and Transverse waves.
masya89 [10]
The answer is C sorry if it’s wrong
4 0
3 years ago
A wheel of diameter 78 cm has an axle of diameter 14.8 cm. A force 150 N is exerted along the rim of the wheel.What force should
bezimeni [28]

Answer:

F = 263.51 N

Explanation:

given,

diameter of wheel = 78 cm

diameter of axle = 14.8 cm

Force exerted on the rim of wheel = 150 N

Force applied outside the axle = ?

To prevent rotation wheel from rotating the Force 'F' should be applied outside of the axle.

Net momentum about the center of mass should be zero

now,

Moment of about center due to 150 N = moment about center due to F on axle

50\times \dfrac{78}{2}=F\times \dfrac{14.8}{2}

           7.4 F = 1950

                F = 263.51 N

Hence, Force exerted outside of the axle in order to prevent the wheel from rotating is equal to 263.51 N.

6 0
4 years ago
A source emits monochromatic light of wavelength 495 nm in air. when the light passes through a liquid, its wavelength reduces t
Katyanochek1 [597]
By definition, the refractive index is
n = c/v
where c =  3 x 10⁸ m/s,  the speed of light in vacuum
v = the speed of light in the medium (the liquid).

The frequency of the light source is
f = (3 x 10⁸ m/s)/(495 x 10⁻⁹ m) = 6.0606 x 10¹⁴ Hz

Because the wavelength in the liquid is 434 nm = 434 x 10⁻⁹ m, 
v = (6.0606 x 10¹⁴ 1/s)*(434 x 10⁻⁹ m) = 2.6303 x 10⁸ m/s

The refractive index is (3 x 10⁸)/(2.6303 x 10⁸) = 1.1406

Answer:  a.  1.14
6 0
3 years ago
What do we call a part of the body with a special function?
murzikaleks [220]
This is called an organ.  Examples of organs are: your heart, brain, lungs, liver, stomach etc.
4 0
4 years ago
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