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Vladimir [108]
3 years ago
6

What does an alpha particle consist of?

Physics
2 answers:
Step2247 [10]3 years ago
8 0

Answer:

C.

Explanation:

i just took the test

antiseptic1488 [7]3 years ago
6 0
The best answer to the question '<span>What does an alpha particle consist of?' would be letter c. An alpha particle consists of 2 protons and 2 neutrons. It is a particle that has no electrons and balances out the positively charged protons. </span>
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When the sun provides energy for photosynthesis, an interaction with the __________ takes place.
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The tensile stress in a thick copper bar is 99.5 % of its elastic breaking point of 13.0× 10¹⁰ N/m² . If a 500-Hz sound wave is
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The speed of the wave in the rod is

The speed of the wave in the rod is $v = \sqrt{\frac{Y}{\rho}} = \sqrt{\frac{20\times 10^{10}\ \mathrm{N/m^2}}{7.86\times 10^3\ \mathrm{kg/m^3}}} = 5044\ \mathrm{m/s}$

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<h3>What is sound wave?</h3>

A sound wave is the pattern of disruption brought on by the movement of energy moving through a medium as it propagates away from the source of the sound (such as air, water, or any other liquid or solid substance). Pressure waves are produced when an item vibrates, such as a ringing phone, and these waves are known as sound waves. The surrounding medium's particles are disturbed by the pressure wave, and those particles disrupt the particles next to them, and so on. Like ocean waves, the disturbance's pattern causes outward movement in all directions. Usually in all directions and with decreased intensity as it gets further away from the source, the wave transmits the sound energy through the medium.

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2 years ago
A man tries to push a 200 kg Car that moves at a acceleration 0.50 m/s2. The man is able to displace the car 10 m. How much work
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The work done by the man pushing the car over the given distance is 1000J.

Given the data in the question;

  • Mass of car; m = 200kg
  • Acceleration of the car; a = 0.5m/s^2
  • Distance covered by the car; d = 10m

Work done; W = \ ?

<h3>Work done</h3>

Work done is simply defined as the energy transfer that takes place when an object is either pushed or pulled over a certain distance by an external force. It is expressed as;

Work\ done = f * d

Where f is force applied and d is distance travelled.

To determine the work done by the man, we first solve for the force applied F.

From Newton's Second Law; Force \ F = m * a

We substitute our given values into the expression

F = m * a \\\\F = 200kg * 0.5m/s^2\\\\F = 100kg.m/s^2

Next we substitute our values into the expression of work done above.

Work \ done = f * d\\\\Work \ done = 100kg.m/s^2 * 10m\\\\Work \ done = 1000kgm^2/s^2\\\\Work \ done = 1000J

Therefore, the work done by the man pushing the car over the given distance is 1000J.

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