PLEASEEE HELPPPPP does anyone know these answers?

A gazelle leaps from a cliff 2.5 m high with a speed of 5.6m/s.

trapecia [35]

Initial speed of Gazelle is along x direction and its value will be

$v_x = 5.6 m/s$

also its initial height is given as

$y = 2.5 m$

Part a)

now from kinematics along Y direction

$\Delta y = v_y t + \frac{1}{2} at^2$

as we know that

$\Delta y = 0$

$v_y = 0$

$a = 9.8 m/s^2$

$2.5 = 0 + \frac{1}{2} (9.8) t^2$

$t = 0.714 s$

Part b)

distance moved horizontally

$\Delta x = v_x t$

as we know that

$v_x = 5.6 m/s$

now we will have

$v_x = 5.6 (0.714) = 4m$

so it will lend at distance of 4 m.

Part c)

final velocity in vertical direction

$v_{fy} = v_y + at$

$v_{fy} = 0 + (9.8)(0.714) = 7 m/s$

$v_x = 5.6 m/s$

so net speed will be

$v^2 = v_x^2 + v_y^2$

$v^2 = 7^2 + 5.6^2$

$v = 8.96 m/s$

7 0

4 years ago

Arrange the following types of photons of electromagnetic radiation in order of decreasing energy: red light, radio, x-rays, γ-r

MrRa [10]

Answer:The correct order is

γ-rays > x-rays> red light > infrared > radio

Explanation:

In the electromagnetic spectrum we have the following electromagnetic radiation Radio waves, infrared radiation, visible light, ultraviolet light, X-ray and gamma rays. Gamma rays have the highest frequency and radio waves the lowest. From the formula;

E=hf, where;

E is energy

h is Planck constant

f is frequency

We can see that the energy of these radiation depends on the magnitude of their frequency. Hence Gamma ray with highest frequency will have the highest energy and radio waves the lowest energy. Red light however is found at the lower end of the visible light spectrum . the correct order is;

γ-rays > x-rays> red light > infrared > radio

8 0

3 years ago

For this quiz, we shall return to the radio control car track that we visited briefly on the last quiz. The track is 10 meters l

Iteru [2.4K]

Answer:

$v=1.54\,\,metres\,\,per\,\,second$

Explanation:

The given equation is $x=x_0+vt$ where $x_0$ denotes initial time in the stopwatch and $x$ denotes the distance covered by car.

As the judge starts her watch at the instant the car passes the 2.0 meter mark $(x_0=2)$ and the judge reads 3.9 seconds on her stopwatch when the car passes the 8.0 meter mark.

Put $x_0=2,\,,\,x=8\,,\,t=3.9$ in equation $x=x_0+vt$

$8=2+3.9t\\8-2=3.9t\\6=3.9v\\v=\frac{6}{3.9}\\ v=1.54\,\,metres\,\,per\,\,second$

3 0

3 years ago

Which of the following water waves has more energy?

Murljashka [212]

A tsunami.........................................................................................................

4 0

4 years ago

Which statement is true about the law of conservation of energy for an object released from a certain height above the ground

gregori [183]

The question is really specific enough, but I will take a guess. If nothing else changes (like the mass or the gravitational constant) then the Potential Energy will increase with an increase in height. Ep will decrease with a decrease in height.

If you are talking about Ke, then the height does not matter unless the object is moving up. Then it slows down. When that happens the Ke decreases because the formula for Ke = 1/2 m v^2. If v becomes less then Ke becomes less.

I suppose you could say if the object is going down and the distance is decreasing then the speed will increase. It's an inverse relationship.

I think you are best talking about Pe.

6 0

4 years ago