PLEASEEE HELPPPPP does anyone know these answers?

A piston-cylinder device contains 3 kg of saturated water vapor at 200 kPa. Now heat is transferred to the system at constant pr

-BARSIC- [3]

Answer:

work done = 117 kJ

Explanation:

given data

mass m = 3 kg

constant pressure P = 200 kPa

temperature T = 200°C

solution

we know that work done by steam is express as

work done = pressure × ΔVolume ....................1

and here ΔVolume = final volume - initial volume

we use here steam table and get at pressure 200 kPa

final specific volume = 1.08052 m³/kg

and

initial specific volume = 0.885735 m³/kg

so here

ΔV = 3 × (1.08052 - 0.885735)

ΔV = 0.584 m³

so put value in equation 1 we get

work done by steam = 200 × 0.584

work done = 117 kJ

6 0

3 years ago

I need help in physics please help me

artcher [175]

The first step is to represent the vectors shown in the image in Cartesian coordinates.

For the vector C we have a magnitude of 4.8 and an angle 22 ° with the axis -y (direction j)

To write this vector in Cartesian coordinates we must find its component in x (address i) and in the y axis.

$x = 4.8sin(22)i\\\\y = 4.8cos(22)(-j)$

So:

$C = 4.8sin(22) i + 4.8cos(22)(-j)\\\\C = 1.798\ i - 4.450\ j$

For Vector B we have a magnitude of 5.6 and an angle of 33 with the -x axis (-i direction)

So:

$x = 5.6cos(33)(-i)\\\\y = 5.6 sin(33)(-j)$

So:

$B = 5.6cos(33)(-i) + 5.6sin(33)(-j)\\\\B = -4.696\ i - 3.05\ j$

Finally the sum of B + C is made component by component in the following way:

$F = (-4.696 +1.798)i + (-4.450 - 3.05)j\\\\F = -2.898\ i - 7.5\ j$

Finally the magnitude of f is:

$|F| = \sqrt{(-2,898)^2 + (-7.5)^2}$

| F | = 8.04

3 0

3 years ago

g A 5.60-kilogram hoop starts from rest at a height 1.80 m above the base of an inclined plane and rolls down under the influenc

swat32

Answer:

4.24m/s

Explanation:

Potential energy at the top= kinetic energy at the button

But kinetic energy= sum of linear and rotational kinetic energy of the hoop

PE= mgh

KE= 1/2 mv^2

RE= 1/2 I ω^2

Where

m= mass of the hoop

v= linear velocity

g= acceleration due to gravity

h= height

I= moment of inertia

ω= angular velocity of the hoop.

But

I = m r^2 for hoop and ω = v/r

giving

m g h = 1/2 m v^2 + 1/2 (m r^2) (v^2/r^2) = 1/2 m v^2 + 1/2 m v^2 = m v^2

and m's cancel

g h = v^2

Hence

v= √gh

v= √10×1.8

v= 4.24m/s

4 0

3 years ago

Read 2 more answers

A heat engine performs (245 + A) J of work in each cycle while also delivering (142 + B) J of heat to the cold reservoir. Find t

Ganezh [65]

Answer:

The value is $\eta = 54.4 \%$

Explanation:

From the question we are told that

The work input is $W = ( 245 + A ) \ J$

The heat delivered is $Q = (142 + B) \ J$

The value of A is A = 14

The value of B is B = 72

Generally the efficiency of the heat engine is mathematically represented as

$\eta = \frac{W}{Q_t}$

Here $Q_t$ is the total out energy produce by the heat engine and this is mathematically represented as

$Q_t= Q + W$

=> $Q_t= 245 + A + 142 + B$

=> $Q_t= 390 + A+B$

So

$\eta = \frac{245 + A }{390 + A+ B}$

=> $\eta = 0.544$

=> $\eta = 0.544 *100$

=> $\eta = 54.4 \%$

5 0

2 years ago

Jane is sliding down a slide. What kind of motion is she demonstrating? A. translational motion B. rotational motion C. vibratio

Andreyy89

A. translational motion

5 0

3 years ago