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3 years ago

7070

Mathematics

1 answer:

SVETLANKA909090 [29]3 years ago

8 0

Answer:

do you want the answer because i am telling your teacher that you are cheating

Step-by-step explanation:

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Choose the graph which represents the solution to the inequality:<br> 3x + 8 ≥ 11

Mashutka [201]

The solution of the inequality is x ≥ 1.

Solution:

Given inequality:

$3 x+8 \geq 11$

To find the solution of the inequality:

$3 x+8 \geq 11$

Subtract 8 from both sides.

$3 x+8-8 \geq 11-8$

$3 x \geq 3$

Divide by 3 on both sides.

$$\frac{3 x}{3} \geq \frac{3}{3}$

On simplifying this, we get

$x \geq 1$

The solution of the inequality is x ≥ 1.

The graph of the solution is attached below.

8 0

3 years ago

DO THIS FAST PLEASE I WILL GIVE BRAINLY CROWN

vekshin1

5 ÷ 1/2 => 5 x 2/1 => 10/1 => 10

8 0

3 years ago

Read 2 more answers

Which of the following could be the perimeter of a rectangle with an area of 24 square inches?

Veronika [31]

Answer: C. 20 inches

Step-by-step explanation:

perimeter= 2 x (4+6)=20 inches

7 0

3 years ago

<img src="https://tex.z-dn.net/?f=%24a%2Ba%20r%2Ba%20r%5E%7B2%7D%2B%5Cldots%20%5Cinfty%3D15%24%24a%5E%7B2%7D%2B%28a%20r%29%5E%7B

riadik2000 [5.3K]

Let

$S_n = \displaystyle \sum_{k=0}^n r^k = 1 + r + r^2 + \cdots + r^n$

where we assume |r| < 1. Multiplying on both sides by r gives

$r S_n = \displaystyle \sum_{k=0}^n r^{k+1} = r + r^2 + r^3 + \cdots + r^{n+1}$

and subtracting this from $S_n$ gives

$(1 - r) S_n = 1 - r^{n+1} \implies S_n = \dfrac{1 - r^{n+1}}{1 - r}$

As n → ∞, the exponential term will converge to 0, and the partial sums $S_n$ will converge to

$\displaystyle \lim_{n\to\infty} S_n = \dfrac1{1-r}$

Now, we're given

$a + ar + ar^2 + \cdots = 15 \implies 1 + r + r^2 + \cdots = \dfrac{15}a$

$a^2 + a^2r^2 + a^2r^4 + \cdots = 150 \implies 1 + r^2 + r^4 + \cdots = \dfrac{150}{a^2}$

We must have |r| < 1 since both sums converge, so

$\dfrac{15}a = \dfrac1{1-r}$

$\dfrac{150}{a^2} = \dfrac1{1-r^2}$

Solving for r by substitution, we have

$\dfrac{15}a = \dfrac1{1-r} \implies a = 15(1-r)$

$\dfrac{150}{225(1-r)^2} = \dfrac1{1-r^2}$

Recalling the difference of squares identity, we have

$\dfrac2{3(1-r)^2} = \dfrac1{(1-r)(1+r)}$

We've already confirmed r ≠ 1, so we can simplify this to

$\dfrac2{3(1-r)} = \dfrac1{1+r} \implies \dfrac{1-r}{1+r} = \dfrac23 \implies r = \dfrac15$

It follows that

$\dfrac a{1-r} = \dfrac a{1-\frac15} = 15 \implies a = 12$

and so the sum we want is

$ar^3 + ar^4 + ar^6 + \cdots = 15 - a - ar - ar^2 = \boxed{\dfrac3{25}}$

which doesn't appear to be either of the given answer choices. Are you sure there isn't a typo somewhere?

7 0

2 years ago

What will it cost to carpet a rectangular floor measuring 12 feet by 15 feet if the carpet costs $ 31.65 per square yard?

kaheart [24]

Answer:

$633

Step-by-step explanation:

You multiply the 12x15 feet by 31.65

8 0

3 years ago