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TEA [102]
3 years ago
11

Slove the simoltanous equation by using substitution or elimination method 5x-3y=1 3x+2y=1​

Mathematics
1 answer:
xxTIMURxx [149]3 years ago
7 0

<u>By substitution method </u>

5x - 3y =1

3x + 2y = 1

_____o____o____

5x - 3y = 1 \\ 5x = 1  +  3y \\ x =  \frac{1 + 3y}{5}

______o____o_____

3x + 2y = 1 \\ 3( \frac{1 + 3y}{5} ) + 2y = 1 \\  \frac{3 + 9y}{5}  + 2y = 1 \\  \frac{3 +9y + 10y}{5}  = 1 \\  \frac{3 + 19y}{5}  = 1 \\ 3 + 19y = (1)(5) \\ 3 + 19y = 5 \\ 19y = 5 - 3 \\ 19y = 2 \\ y =  \frac{2}{19}

______o_____o____

x =  \frac{1 + 3y}{5}  =  \frac{1 + 3 \frac{2}{19} }{5} \\ x =  \frac{1 +  \frac{6}{19} }{5}  =  \frac{ \frac{19 + 6}{19} }{5}   =  \frac{ \frac{25}{19} }{5}  \\ x =  \frac{25}{19}  \div 5 \\ x =  \frac{25}{19}  \times  \frac{1}{5}  \\ x =  \frac{5}{19}

I hope I helped you^_^

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