<span>1, 2, 3, 5, 6, 10, 15, 30 represent the factors of 30, the GCF. </span>
Answer:
shade two rows. 'uwu. ____
Given:
The function is
![f(x)=\dfrac{4x}{x^2-16}](https://tex.z-dn.net/?f=f%28x%29%3D%5Cdfrac%7B4x%7D%7Bx%5E2-16%7D)
To find:
The asymptotes and zero of the function.
Solution:
We have,
![f(x)=\dfrac{4x}{x^2-16}](https://tex.z-dn.net/?f=f%28x%29%3D%5Cdfrac%7B4x%7D%7Bx%5E2-16%7D)
For zeroes, f(x)=0.
![\dfrac{4x}{x^2-16}=0](https://tex.z-dn.net/?f=%5Cdfrac%7B4x%7D%7Bx%5E2-16%7D%3D0)
![4x=0](https://tex.z-dn.net/?f=4x%3D0)
![x=0](https://tex.z-dn.net/?f=x%3D0)
Therefore, zero of the function is 0.
For vertical asymptote equate the denominator of the function equal to 0.
![x^2-16=0](https://tex.z-dn.net/?f=x%5E2-16%3D0)
![x^2=16](https://tex.z-dn.net/?f=x%5E2%3D16)
Taking square root on both sides, we get
![x=\pm \sqrt{16}](https://tex.z-dn.net/?f=x%3D%5Cpm%20%5Csqrt%7B16%7D)
![x=\pm 4](https://tex.z-dn.net/?f=x%3D%5Cpm%204)
So, vertical asymptotes are x=-4 and x=4.
Since degree of denominator is greater than degree of numerator, therefore, the horizontal asymptote is y=0.
Answer:
Step-by-step explanation: once you add up all the numbers you get 74. To find the mean add up all the numbers, then divide by how many numbers there are. In other words it is the sum divided by the count. Once you divide, you will get 18.5 as the answer for the mean