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nika2105 [10]
2 years ago
7

Please help i really don't understand

Mathematics
1 answer:
Natali5045456 [20]2 years ago
7 0

Answer:

  80 square units

Step-by-step explanation:

The area formula refers to a generic triangle ABC in which side lengths 'a' and 'b' are known and angle C is between those sides.

In the given figure, we have known side lengths of 12 and 14, and the angle between them is 72°.

Putting these numbers into the formula, we find the area to be ...

  A = (1/2)(12)(14)sin(72°) ≈ 79.9 ≈ 80 . . . . square units

The area of the triangle is about 80 square units.

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If z^2+1/z^2=11 , find the value of z^3-1/z^3,using only the positive value of z-1/z
vredina [299]
Hello,

Let's assume

t=z- \dfrac{1}{z} \\\\

t^2=z^2-2+ \dfrac{1}{z^2}= 11-2=9==\ \textgreater \ t=3\\\\

t^3=z^3-3z^2* \dfrac{1}{z} +3z* \dfrac{1}{z^2} - \dfrac{1}{z^3} \\\\
=z^3 - \dfrac{1}{z^3} -3(z-\dfrac{1}{z})\\\\
z^3 - \dfrac{1}{z^3}=t^3+3t=3^3+9=27+9=36



7 0
3 years ago
PLEASE HELP I WILL MARK BRAINLIEST!<br> Question is in the image.
deff fn [24]

Answer:

8

Step-by-step explanation:

The interquartile range of a data set is the difference between the upper and lower quartiles.

First, put the values in order from least to greatest:

8, 9, 9, 9, 10, 11, 13, 15, 17, 18, 22

To find the upper quartile, we need to first find the median.

The median of this data set is 11, because it is in the middle of the values.

The upper quartile is the median of all the numbers to the left of 11.

The median of 8, 9, 9, 9, and 10 is 9, because it's in the middle.

So the upper quartile is 9.

The lower quartile is the same, but to the right of 11. The median of 13, 15, 17, 18, and 22 is 17 because it's in the middle.

Now, to find the interquartile range, find the difference between 18 and 9.

17 - 9 = 8

5 0
2 years ago
Find the midpoint of the line segment shown below.
balu736 [363]

Answer:

x²-6x+y²-4y=-4

Step-by-step explanation:

We know the circle equation stands like this:

(x-a)² + (y-b)² = R²

and (a,b) is center

and R stands for Radius

so in this case:

center = (3,2)

R = 3

So

(x-3)² + (y-2)² = 9

x²-6x+9 + y²-4y+4=9

x²-6x+y²-4y=-4

7 0
2 years ago
Does this graph represent a function? Why or why not?
dlinn [17]
The answer is 100 percent B
8 0
1 year ago
Find the minimum value of the region formed by the system of equations and functions below.
Naily [24]

Answer:

  A.  -12

Step-by-step explanation:

A graph shows the vertices of the feasible region to be (0, 6), (3, 0) and (0, -3). Of these, the one that minimizes f(x, y) is (0, -3). The minimum value is ...

  f(0, -3) = 3·0 + 4(-3) = -12

_____

<em>Comment on the graph</em>

Here, three regions overlap to form the region where solutions are feasible. By reversing the inequality in each of the constraints, <em>the feasible region shows up on the graph as a white space</em>, making it easier to identify. The corner of the feasible region that minimizes the objective function is the one at the bottom, at (0, -3).

7 0
3 years ago
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