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Bess [88]
3 years ago
6

PLS HELP TIMED QUIZ The size of a television screen is given as the length of the diagonal. If a television is advertised as hav

ing a 30-inch screen and a height of 18 inches, what is the width of the television? Answer options with 5 optionsA.4.9 inchesB.9.8 inchesC.12 inchesD.24 inchesE.35 inches
Mathematics
1 answer:
grin007 [14]3 years ago
5 0

Answer:

D.24

Pythagorean states:

hypotenuse^2 = side1^2 + side2^2

30^2 = 18^2 + side2^2

side2^2 = 30^2 - 18^2

side2^2 = 900 - 324

side2^2 = 576

side2 = sqr root 576

side2 = 24

Source: http://www.1728.org/pythgorn.htm

Step-by-step explanation:

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debit card

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Manny buys four boxes of straws for his restaurant there are 500 straws in each box how many straws does he buy
Karolina [17]

Answer:

2000 straws

Step-by-step explanation:

4 × 500 = 2000

4 0
3 years ago
Can someone help me with this problem?
Lena [83]
The only answer that makes sense to me is B.
3 0
3 years ago
453.2 divided by 14 (Round to the nearest tenth)
Bond [772]

Answer:

{453.2 \div 14} \\  =  \frac{453.2}{14}  \\  \\  = { \boxed{32.4}}

3 0
3 years ago
Read 2 more answers
b) If parametric equations of a flow line are x = x(t), y = y(t), explain why these functions satisfy the differential equations
sineoko [7]

Answer:

The equation of the the flow line that passes through the point (x, y) = (−1, −1) is

In y + In x = 0 or in another form, xy = 1.

Step-by-step explanation:

The pathline equation for a vector field is given by F(x,y) = xî - yj

The velocity vector field for the streamline of the flow is given by

V(x, y) = (dx/dt)î + (dy/dt)j

From the question, it is given that

(dx/dt) = x

(dy/dt) = -y

Hence, the velocity vector field for the streamline of the flow in question is

V(x, y) = xî - yj

which coincides with the pathline vector field of the flow.

The only time the pathline and streamline vector field coincide and have the same equation is when the flow is a steady state flow.

That is, the properties of the fluid flowing isn't changing with time!

Hence, this flow is a steady state flow!

We're told to solve the differential equation.

(dx/dt) = x

(dy/dt) = -y

but

(dy/dx) = (dy/dt) × (dt/dx)

(dy/dx) = -y/x

(dy/y) = -(dx/x)

∫(dy/y) = -∫ (dx/x)

In y = - In x + c

where c is the constant of integration

In y + In x = c

In (xy) = c

Inserting the values of (x, y) given in the question,

In (-1 × -1) = c

In 1 = c

0 = c

c = 0

In y + In x = 0

In (yx) = 0

xy = e⁰ = 1

xy = 1

So, the equation of the the flow line that passes through the point (x, y) = (−1, −1) is

In y + In x = 0 or in another form, xy = 1

Hope this Helps!!!

4 0
3 years ago
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