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2 years ago

7

A tree that is 100 feet tall casts a shadow that is 150 feet long. Determine the angle at which the rays of the sun hit the grou

nd.

2 answers:

Fofino [41]2 years ago

8 0

The answer is 33 degrees. Hope this helped <span />

Veronika [31]2 years ago

4 0

You would use TAN.

equation: tan?=150/100

answer: about 56.3

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The Lacrosse booster club is holding a raffle for a fundraiser. They will sell 100 tickets for $5 each and select 4 winners. All

Nadusha1986 [10]

Answer:

<h2>There are 3,921,225 ways to select the winners.</h2>

Step-by-step explanation:

This problem is about combinations with no repetitions, because the same person can't win four times. It's a combinaction because the order of winning doesn't really matter.

Combinations without repetitions are defined as

$C_{n}^{r} =\frac{n!}{r!(n-r)!}$

Where $n=100$ and $r=4$ .

Replacing values, we have

$C_{100}^{4} =\frac{100!}{4!(100-4)!}=\frac{100!}{4! 96!}=\frac{100 \times 99 \times 98 \times 97 \times 96!}{4! \times 96!}= \frac{94,109,400}{24}= 3,921,225$

Therefore, there are 3,921,225 ways to select the winners.

Additionally, as you can imagine, the probability of winning is extremely low, it would be 3,921,225 to 1.

3 0

3 years ago

Triangle OPQ is similar to triangle RST. Find the measure of side RS. Round your answer to the nearest tenth if necessary. OPQR

Andrews [41]

Answer:

RS = 75.3

Step-by-step explanation:

You need to set up the proportion of corresponding sides.

$\frac{PQ}{ST} = \frac{PO}{RS}$

$\frac{7}{31} = \frac{17}{RS}$

7(RS) = 31(17)

= 527

RS = 527/7 = 75.2857...

= 75.3

3 0

3 years ago

Which would be appropriate compatible numbers to use to estimate ( 19 4 5 ) ( 4 6 ) ? Using this compatible number, what is the

MA_775_DIABLO [31]

The appropriate compatible numbers to use to estimate would be 20(1/2)

estimated product is 10, took the quiz :)

8 0

3 years ago

The function H(t) = −16t2 + 60t + 95 shows the height H(t), in feet, of a projectile after t seconds. A second object moves in t

EleoNora [17]

H(t) = -16t² + 60t + 95
g(t) = 20 + 38.7t

h(1) = -16(1²) + 60(1) + 95 = -16 + 60 + 95 = -16 + 155 = 139
h(2) = -16(2²) + 60(2) + 95 = -16(4) + 120 + 95 = -64 + 215 = 151
h(3) = -16(3²) + 60(3) + 95 = -16(9) + 180 + 95 = -144 + 275 = 131
h(4) = -16(4²) + 60(4) + 95 = -16(16) + 240 + 95 = -256 + 335 = 79

g(1) = 20 + 38.7(1) = 20 + 38.7 = 58.7
g(2) = 20 + 38.7(2) = 20 + 77.4 = 97.4
g(3) = 20 + 38.7(3) = 20 + 116.1 = 136.1
g(4) = 20 + 38.7(4) = 20 + 154.8 = 174.8

Between 2 and 3 seconds.
The range of the 1st object is 151 to 131.
The range of the 2nd object is 97.4 to 136.1

h(t) = g(t) ⇒ 131 = 131

<span>It means that the point where the 2 objects are equal is the point where the 1st object is falling down while the 2nd object is still going up. </span>

5 0

3 years ago

??????????????????????????????

marissa [1.9K]

Answer:

2 and 3

Step-by-step explanation:

7 0

2 years ago