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Slav-nsk [51]
3 years ago
13

2 3/4+12 1/2 = what is it

Mathematics
2 answers:
natta225 [31]3 years ago
8 0
An equation
what else could it be?
Andru [333]3 years ago
7 0

Answer: 15\frac{1}{4}

Step-by-step explanation:

2\frac{3}{4}+12\frac{1}{2}

Step 1: Add the whole numbers

2 + 12 = 14

Step 2: Combine fractions

\frac{3}{4} + \frac{1}{2}

LCD

2 \times 4 = 4

Add numerators

3+1 = 5

= \frac{5}{4}

14+\frac{5}{4}

Step 3: Add whole numbers

14+1=15

Step 4: Combine the remaining

15\frac{1}{4}

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5x – 4y = -10<br><br> y= 2x – 5 <br><br> what's x and what's y!!
IgorLugansk [536]
X=-2+ 4/5y, y= no real number
7 0
3 years ago
Read 2 more answers
NEED HELP PLEASE I need number 3 and 4 please if anybody can help
zepelin [54]

Answer:

top bar on 3. 120 dollars for strawberry milk per month

bottom bar on 3. 100 dollars chocolate milk per month

#4. bars help an individual know information visually and may help an individual understand better.

6 0
2 years ago
What is the slope the line that passes through the points:<br> (-6, 14), (2, -18)
Vesna [10]

Hey there! I'm happy to help!

Here's how to find the slope given any two points.

Subtract the y values.

14-(-18+-14+18=32

Subtract the x values.

-6-2=-8

And divide those.

32/-8=-4

The slope is -4.

Have a wonderful day! :D

5 0
3 years ago
P^2 - 17p + 72 factor the trinomial. enter smaller number first ? answer (p+?)(p+?)
klio [65]

Answer:

(p - 8)(p - 9)

Step-by-step explanation:

We need  2 numbers whose product is + 72 and whose sum = -17.

They are -8 and -9


3 0
3 years ago
A set of data has a normal distribution with a mean of 5.1 and a standard deviation of 0.9. Find the percent of data between 4.2
Yuliya22 [10]

A set of data has a normal distribution with a mean of 5.1 and a standard deviation of 0.9. Find the percent of data between 4.2 and 5.1.

Answer: The correct option is B) about 34%

Proof:

We have to find P(4.2

To find P(4.2, we need to use z score formula:

When x = 4.2, we have:

z = \frac{x-\mu}{\sigma}

          =\frac{4.2-5.1}{0.9}=\frac{-0.9}{0.9}=-1

When x = 5.1, we have:

z = \frac{x-\mu}{\sigma}

          =\frac{5.1-5.1}{0.9}=0

Therefore, we have to find P(-1

Using the standard normal table, we have:

P(-1= P(z

                               =0.50-0.1587

                               =0.3413 or 34.13%

                               = 34% approximately

Therefore, the percent of data between 4.2 and 5.1 is about 34%

7 0
3 years ago
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