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2 years ago

Please help me, I’m not that smart!

Mathematics

1 answer:

Oxana [17]2 years ago

8 0

Answer:

$\frac{16 {d}^{3} }{ {c}^{2} }$

Step-by-step explanation:

${4}^{2} {c}^{ - 2} {d}^{3} {e}^{0}$

➡️ $16 {c}^{ - 2} {d}^{3} \times 1$

➡️ $16 {c}^{ - 2} {d}^{3}$

➡️ $16 \times \frac{1}{ {c}^{2} } \times {d}^{3}$

➡️ $\frac{16 {d}^{3} }{ {c}^{2} }$

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After Ricardo received his allowance for the week, he went to the mall with some friends. He spent half of his allowance on a ne

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3 years ago

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The cosine of 23° is equivalent to the sine of what angle

Archy [21]

Answer:

So 67 degrees is one value that we can take the sine of such that is equal to cos(23 degrees).

(There are more values since we can go around the circle from 67 degrees numerous times.)

Step-by-step explanation:

You can use a co-function identity.

The co-function of sine is cosine just like the co-function of cosine is sine.

Notice that cosine is co-(sine).

Anyways co-functions have this identity:

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$\sin(90^\circ-x)=\cos(x)$

You can prove those drawing a right triangle.

I drew a triangle in my picture just so I can have something to reference proving both of the identities I just wrote:

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So 90+x+(missing angle)=180.

Let's solve for the missing angle.

Subtract 90 on both sides:

x+(missing angle)=90

Subtract x on both sides:

(missing angle)=90-x.

So the missing angle has measurement (90-x).

So cos(90-x)=a/c

and sin(x)=a/c.

Since cos(90-x) and sin(x) have the same value of a/c, then one can conclude that cos(90-x)=sin(x).

We can do this also for cos(x) and sin(90-x).

cos(x)=b/c

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cos(23)=sin(90-23)

cos(23)=sin(67)

So 67 degrees is one value that we can take the sine of such that is equal to cos(23 degrees).

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Step by step:

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