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2 years ago

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PART A. A fruit juice recipe uses three ingredients. Two of the ingredients use a ratio of 2 ounces of pineapple juice to 5 ounc

es of fruit punch.Graph a line on the coordinate plane to represent this relationship.
PART B. Create an equation to represent this relationship let X represent ounces of pineapple juice. Let Y represent ounces of fruit punch. the picture is apart of Part A

1 answer:

Rashid [163]2 years ago

8 0

Answer:

(B) The equation of line is 5 X = 2 Y.

Step-by-step explanation:

2 ounces of pineapple juice

5 ounces of fruit punch

Other is 4 ounces pineapple juice and 10 ounces fruit punch

(A) Graph is shown below:

(B) Let X is the pineapple juice and Y is the fruit punch

(2, 5) and (4, 10)

So, the equation of line is

$Y - 5 = \frac{10-5}{4-2}\times (x -2)\\\\Y-5=2.5 (X-2)\\\\Y - 5 = 2.5 X - 5 \\\\2.5 X = Y\\\\ 5 X = 2 Y$

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${6}^{ - 2} \\ \frac{1}{ {6}^{2} } \\ \frac{1}{36}$

The answer is C

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Answer:

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Step-by-step explanation:

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2 years ago

Plzz HELP FOR POINTS AND BRAINLIST ANSWER

storchak [24]

A)Plugging in our initial statement values of y = 16 when x = 10, we get:

16 = 10k

Divide each side by 10 to solve for k:

16/10=

k = 1.6

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Because we have found our relationship constant k = 1.6, we form our new variation equation:

y = 1.6x

Since we were given that x, we have

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2 years ago

Choose the solution(s) of the following system of equations x2 + y2 = 6 x2 – y = 6

ElenaW [278]

<h2>Answer</h2>

$x=\sqrt{6}, y=0\\ x=-\sqrt{6} , y=0\\x=\sqrt{5} , y=-1\\x=-\sqrt{5} , y=-1$

Or as ordered pairs: $(\sqrt{6} ,0),(-\sqrt{6} ,0),(\sqrt{5} ,-1),(-\sqrt{5} ,-1)$

<h2>Explanation</h2>

Lets solve our system of equations step by step

$x^2+y^2=6$ equation (1)

$x^2-y=6$ equation (2)

1. Solve for $x^2$ in equation (2)

$x^2-y=6$

$x^2=6+y$ equation (3)

2. Replace equation (3) in equation (1) and solve for $y$

$x^2+y^2=6$

$6+y+y^2=6$

$y^2+y=0$

$y(y+1)=0$

$y=0$ or $y=-1$

3. Replace the values of $y$ in equation (3) and solve for $x$

- For $y=0$

$x^2=6+y$

$x^2=6$

$x=\sqrt{6}$ or $x=-\sqrt{6}$

- For $y=-1$

$x^2=6+y$

$x^2=6-1$

$x^2=5$

$x=\sqrt{5}$ or $x=-\sqrt{5}$

So, the solutions of our system of equation are:

$x=\sqrt{6}, y=0\\ x=-\sqrt{6} , y=0\\x=\sqrt{5} , y=-1\\x=-\sqrt{5} , y=-1$

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2 years ago

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