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zepelin [54]
2 years ago
14

A forestal station receives the locations of two fires, one of them in a forest located 11 Km heading N69°W from the station. Th

e second fire in a forest 21 Km heading S35°E. Calculate the distance on straight line between the two fires. Round your answer to one decimal place.
Mathematics
1 answer:
loris [4]2 years ago
8 0

Answer:

  30.7 km

Step-by-step explanation:

The distance between the two fires can be found using the Law of Cosines. For ΔABC in which sides 'a' and 'b' are given, along with angle C, the third side is ...

  c = √(a² +b² -2ab·cos(C))

The angle measured between the two fires is ...

  180° -(69° -35°) = 146°

and the distance is ...

  c = √(11² +21² -2(11)(21)cos(146°)) ≈ √945.015

  c ≈ 30.74

The straight-line distance between the two fires is about 30.7 km.

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3 years ago
Suppose it takes 2 1/2 h to drive from your house to the lake at 48 mi/h. How long will your return trip take at 40 mi/h?
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Answer

The distance from the house to the lake is (2.5 hr)*(48 mi/hr) = 120 miles. The rerurn trip would take (120 mi)/(40 mi/hr) = 3 hours. Distance equals rate times time, so the distance to the lake is 2 1/2 hours times 48 miles per hour.

I hope this helps

4 0
2 years ago
2. Given a quadrilateral with vertices (−1, 3), (1, 5), (5, 1), and (3,−1):
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<h2>Explanation:</h2>

In every rectangle, the two diagonals have the same length. If a quadrilateral's diagonals have the same length, that doesn't mean it has to be a rectangle, but if a parallelogram's diagonals have the same length, then it's definitely a rectangle.

So first of all, let's prove this is a parallelogram. The basic definition of a parallelogram is that it is a quadrilateral where both pairs of opposite sides are parallel.

So let's name the vertices as:

A(-1,3) \\ \\ B(1,5) \\ \\ C(5,1) \\ \\ D(3,-1)

First pair of opposite sides:

<u>Slope:</u>

\text{For AB}: \\ \\ m=\frac{5-3}{1-(-1)}=1 \\ \\ \\ \text{For CD}: \\ \\ m=\frac{1-(-1)}{5-3}=1 \\ \\ \\ \text{So AB and CD are parallel}

Second pair of opposite sides:

<u>Slope:</u>

\text{For BC}: \\ \\ m=\frac{1-5}{5-1}=-1 \\ \\ \\ \text{For AD}: \\ \\ m=\frac{-1-3}{3-(-1)}=-1 \\ \\ \\ \text{So BC and AD are parallel}

So in fact this is a parallelogram. The other thing we need to prove is that the diagonals measure the same. Using distance formula:

d=\sqrt{(y_{2}-y_{1})^2+(x_{2}-x_{1})^2} \\ \\ \\ Diagonal \ BD: \\ \\ d=\sqrt{(5-(-1))^2+(1-3)^2}=2\sqrt{10} \\ \\ \\ Diagonal \ AC: \\ \\ d=\sqrt{(3-1)^2+(-5-1)^2}=2\sqrt{10} \\ \\ \\

So the diagonals measure the same, therefore this is a rectangle.

5 0
3 years ago
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A basket contains 12 apples and some other fruit
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Answer:

Step-by-step explanation:

subtract 9 from both sides

x=3

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