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Burka [1]
2 years ago
13

A cyclist travels 5 miles in 15 minutes. What is her average speed in mph?

Mathematics
1 answer:
Ber [7]2 years ago
6 0
S=d/t

15 minutes = 0.25 hour

S=5/0.25

S= 20 miles per hour
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2x - 1 = 0 is a quadratic equation. <br> True False
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I believe the answer is false

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3 years ago
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Help meez 40 pts use surface area formula of cylinder that is for Lateral surface area and for total surface area
jeka94

Answer:So the radius of the cylinder is 2.65 cm.

A cylinder can be defined as a solid figure that is bound by a curved surface and two flat surfaces. The surface area of a cylinder can be found by breaking it down into 2 parts:

1.  The two circles that make up the caps of the cylinder.

2.  The side of the cylinder, which when "unrolled" is a rectangle.

The area of each end cap can be found from the radius r of the circle, which is given by:

A = πr2

Thus the total area of the caps is 2πr2.

The area of a rectangle is given by:

A = height × width

The width is the height h of the cylinder, and the length is the distance around the end circles, or in other words the perimeter/circumference of the base/top circle and is given by:

P = 2πr

Thus the rectangle's area is rewritten as:

A = 2πr × h

Combining these parts together we will have the total surface area of a cylinder, and the final formula is given by:

A = 2πr2 + 2πrh

where:

π  is Pi, approximately 3.142

r  is the radius of the cylinder

h  height of the cylinder

By factoring 2πr from each term we can simplify the formula to:

A = 2πr(r + h)

The lateral surface area of a cylinder is simply given by: LSA = 2πr × h.

Example 1: Find the surface area of a cylinder with a radius of 4 cm, and a height of 3 cm.

Solution:

SA = 2 × π × r2 + 2 × π × r × h

SA = 2 × 3.14 × 42 +  2 × 3.14 × 4 × 3

SA = 6.28 × 16 + 6.28 × 12

SA = 100.48 + 75.36

SA = 175.84

Surface area = 175.84 cm2

Example 2: Find the surface area of the cylinder with a radius of 5.5cm and height of 10cm.

Solution:

The radius of cylinder = 5.5 cm.

The height of cylinder = 10 cm.

The total surface area of the cylinder is therefore:

TSA = 2πr(r+h)

TSA = 11π (5.5+10)

TSA = 170.5 π

TSA = 535.6 cm2

Example 3: Find the total surface area of a cylindrical tin of radius 17 cm and height 3 cm.

Solution:

Again as in the previous example:

TSA = 2πr(r+h)

TSA = 2π× 17(17+3)

TSA = 2π×17×20

TSA = 2136.56 cm2

Example 4: Find the surface area of the cylinder with radius of 6 cm and height of 9 cm.

Solution:

The radius of cylinder: r = 6 cm

The height of cylinder: h = 9 cm

Total surface area of cylinder is therefore:

TSA = 2πr(r + h)

TSA = 12π (6+9)

TSA = 180 π

TSA = 565.56 cm2

Example 5: Find the radius of cylinder whose lateral surface area is 150 cm2 and its height is 9 cm.

Solution:

Lateral surface area of cylinder is given by:

LSA = 2πrh

Given that:

LSA = 150cm2

h = 9cm

π is the constant and its value = 3.14

Substitute the values in the formula and find the value of r by isolating it from the equation:

LSA = 2πrh

150 = 2× π × r × 9

r = 150 / (2×9× π)

r = 2.65cm

So the radius of the cylinder is 2.65 cm.

5 0
2 years ago
the height in feet above the ground of an arrow after it is shot can be modeled by y=-16r^2+63r+4.Can the arrow pass over a tree
miss Akunina [59]

Answer:

yes

Step-by-step explanation:

y=-16r^2+63r+4

maximum value of y :

y'=0

-32r +63=0

r= 63/32

y = -16(63/32)²+63(63/32)+4

= -4 + 124 + 4 = 124 ft

124 > 68

the Arrow can pass over the tree

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3 years ago
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dimulka [17.4K]

The midpoint would be (-2, -1)

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3 years ago
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The width of a rectangle is increasing at a rate of 2 cm/sec, while the length increases at 3 cm/sec. At what rate is the area i
lorasvet [3.4K]

Answer:

The area of the rectangle is increasing at a rate of  22\ cm^2/s.

Step-by-step explanation:

Given : The width of a rectangle is increasing at a rate of 2 cm/ sec. While the length increases at 3 cm/sec.

To find : At what rate is the area increasing when w = 4 cm and I = 5 cm?

Solution :

The area of the rectangle with length 'l' and width 'w' is given by  A=l w

Derivative w.r.t  't',

\frac{dA}{dt}=w\frac{dl}{dt}+l\frac{dw}{dt}

Now, we have given

\frac{dl}{dt}=3\ cm/s

l=5\ cm

\frac{dw}{dt}=2\ cm/s

w=4\ cm

Substitute all the values,

\frac{dA}{dt}=(4)(3)+(5)(2)

\frac{dA}{dt}=12+10

\frac{dA}{dt}=22\ cm^2/s

Therefore, the area of the rectangle is increasing at a rate of  22\ cm^2/s.

4 0
3 years ago
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