Question

1^2 + 2^2 + 3^2 +.... + 28^2 + 29^2 + 30^2 = ...... Find the value Thank you!

Answer 1

Step-by-step explanation:

The sum of consecutive squares is

$1^2+2^2+\dots+n^2=\frac16n(n+1)(2n+1)$

Therefore

$1^2+2^2+\dots+30^2=\frac16(30)(31+1)(2\cdot30+1) = 9455$