Answer:
- def getLargest(number_list):
- new_list = []
-
- for x in number_list:
- if(isinstance(x, int)):
- new_list.append(x)
-
- largest = max(new_list)
-
- return largest
Explanation:
Firstly, create a function <em>getLargest()</em> that take one input parameter, <em>number_list</em>.
The function will filter out the float type number from the list by using <em>isinstance() </em>method (Line 5). This method will check if a current x value is an integer. If so, the x value will be added to <em>new_list</em>.
Next, use Python built-in <em>max</em> function to get the largest integer from the <em>new_list </em>and return it as output.
Answer:
Following is the code for filter:
public class filter
{ public static void main(String[] args)
{ int x = StdIn.readInt();
System.out.print(" " + x + " ");
while(!StdIn.isEmpty())
{ int y = StdIn.readInt();
if(y != x)
System.out.print(" " + y + " ");
x = y;
}
}
}
Explanation:
- A public class filter is used.
- The main function will accept a single argument as string[], it is also known as java command line argument.
- Now the Stdln.readInt is used to read the integers in the sequence and store it in integer x.
- The value stored in variable x will be printed using System.out.print
- Now unless the Stdln.readInt gets an empty value, check each value of sequence and store in variable y.
- If y is not equal to previous value x, print it and shift the value of y into x.
- Repeat the loop again.
i hope it will help you!
