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ad-work [718]
3 years ago
7

(To be answered in the next 20 minutes)

Mathematics
1 answer:
g100num [7]3 years ago
6 0

Answer:

1.) 9/5 or 1.8 or 1 4/5

2.) 17/2 or .53125 or 8 1/2

You might be interested in
Describe the accumulated value a of the sum of money P the principal after two years at annual percent rich are in the decimal f
elena-14-01-66 [18.8K]

In order to calculate the value of t, we can use the given formula with the values P = 6000, A = 2P and i = 11% = 0.11:

\begin{gathered} 2\cdot6000=6000\cdot e^{0.11t}\\ \\ 2=e^{0.11t}\\ \\ \ln2=\ln e^{0.11t}\\ \\ 0.693147=0.11t\\ \\ t=\frac{0.693147}{0.11}=6.3 \end{gathered}

Therefore the time needed is t = 6.3 years.

8 0
1 year ago
Find the value of x plz :(
lutik1710 [3]

Answer:

stop

Step-by-step explanation:

stop using this app, the chances of you actually getting a helpful response or even one at all are so slim, just pay an actual tutor at this point

6 0
3 years ago
Use the three steps to solve the problem.
Flauer [41]

The two numbers are 8,13.

Step-by-step explanation:

Let,

smaller number = x

Larger number = x+5

According to given statement;

Smaller number + Bigger number = 3x-3

x+(x+5)=3x-3\\x+x+5=3x-3\\2x+5+3=3x\\8 = 3x-2x\\8=x\\x=8

Smaller number = 8

Larger number = 8+5 = 13

The two numbers are 8,13.

Keywords: algebraic equation, addition

Learn more about addition at:

  • brainly.com/question/11229113
  • brainly.com/question/11234838

#LearnwithBrainly

7 0
4 years ago
Read 2 more answers
Please help me or i will fail
dusya [7]
Find area of square: 7^2 = 49

Find radius of circle: 7/2=3.5

find area of circle: 3.5^2*3.14=38.465

Remove area of circle from area of square:
49-38.465=10.535 cm^2

Answer A is the correct one :)
4 0
3 years ago
The score of golfers for a particular course follows a normal distribution that has a mean of 73 and a standard deviation of 3.
Artemon [7]

Answer:

P(X \geq 74) = 0.3707

Step-by-step explanation:

We are given that the score of golfers for a particular course follows a normal distribution that has a mean of 73 and a standard deviation of 3.

Let X = Score of golfers

So, X ~ N(\mu=73,\sigma^{2}=3^{2})

The z score probability distribution is given by;

           Z = \frac{X-\mu}{\sigma} ~ N(0,1)

where, \mu = population mean = 73

           \sigma = standard deviation = 3

So, the probability that the score of golfer is at least 74 is given by = P(X \geq 74)

 P(X \geq 74) = P( \frac{X-\mu}{\sigma} \geq \frac{74-73}{3} ) = P(Z \geq 0.33) = 1 - P(Z < 0.33)

                                               =  1 - 0.62930 = 0.3707                  

Therefore, the probability that the score of golfer is at least 74 is 0.3707 .

3 0
3 years ago
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