Answer:
The z-score for the 34-week gestation period baby is 0.61
Step-by-step explanation:
The formula for calculating a z-score is is z = (x-μ)/σ,
where x is the raw score,
μ is the population mean
σ is the population standard deviation.
We are told in the question that:
Babies born after a gestation period of 32-35 weeks have a mean weight of 2600 grams and a standard deviation of 660 grams. Also, we are supposing a 34-week gestation period baby weighs 3000grams
The z-score for the 34-week gestation period baby is calculated as:
z = (x-μ)/σ
x = 3000, μ = 2600 σ = 660
z = 3000 - 2600/660
= 400/660
=0.6060606061
Approximately, ≈ 0.61
Answer:
Step-by-step explanation:
4/7 x + 70 cm^3 = 3/4 x Subtract 4/7 x from both sides
3/4 x - 4/7 x = 70 cm^3 The lowest common denominator is 28
5x = 70*28
5x = 1960 Divide by 5
x = 1960/5
x = 392 cc
Step-by-step explanation:
1. yes 4+16 = 20
2. yes 32 - 4 = 28
3. yes 4(10) = 40
4. no 24/6 = 4
The answer is 270, the pattern is multiplying by 3. So, 10 • 3 = 30 30 • 3 = 90 90 • 3 = 270, and so on. Hope this helps! Let me know if you need any further assistant.
Answer:
The absolute number of a number a is written as
|a|
And represents the distance between a and 0 on a number line.
An absolute value equation is an equation that contains an absolute value expression. The equation
|x|=a
Has two solutions x = a and x = -a because both numbers are at the distance a from 0.
To solve an absolute value equation as
|x+7|=14
You begin by making it into two separate equations and then solving them separately.
x+7=14
x+7−7=14−7
x=7
or
x+7=−14
x+7−7=−14−7
x=−21
An absolute value equation has no solution if the absolute value expression equals a negative number since an absolute value can never be negative.
The inequality
|x|<2
Represents the distance between x and 0 that is less than 2
Whereas the inequality
|x|>2
Represents the distance between x and 0 that is greater than 2
You can write an absolute value inequality as a compound inequality.
−2<x<2
This holds true for all absolute value inequalities.
|ax+b|<c,wherec>0
=−c<ax+b<c
|ax+b|>c,wherec>0
=ax+b<−corax+b>c
You can replace > above with ≥ and < with ≤.
When solving an absolute value inequality it's necessary to first isolate the absolute value expression on one side of the inequality before solving the inequality.
Step-by-step explanation:
Hope this helps :)
